Ars*_*ray 31 java android http-get http-post
我有一个涉及httprequest的错误,有时会发生这种错误,因此我想在发生这种情况时记录HttpGet和HttpPost请求的内容.
所以,让我们说,我创建像这样的HttpGet:
HttpGet g = new HttpGet();
g.setURI(new URI("http://www.google.com"));
g.setHeader("test", "hell yeah");
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这是我想要的字符串表示:
GET / HTTP/1.1
Host: www.google.com
test: hell yeah
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有了post请求,我还想获得内容字符串.
在java for android中最简单的方法是什么?
Jun*_*san 74
您可以使用以下方式打印请求类型:
request.getMethod();
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你可以打印这里提到的所有标题:
Enumeration<String> headerNames = request.getHeaderNames();
while(headerNames.hasMoreElements()) {
String headerName = headerNames.nextElement();
System.out.println("Header Name - " + headerName + ", Value - " + request.getHeader(headerName));
}
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要打印所有请求参数,请使用以下命令:
Enumeration<String> params = request.getParameterNames();
while(params.hasMoreElements()){
String paramName = params.nextElement();
System.out.println("Parameter Name - "+paramName+", Value - "+request.getParameter(paramName));
}
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request 是的例子 HttpServletRequest
您可以根据需要美化输出.
这应该对调试更有帮助。@Juned Ahsan 的回答不会指定完整的 URL,也不会打印多个标题/参数。
private String httpServletRequestToString(HttpServletRequest request) {
StringBuilder sb = new StringBuilder();
sb.append("Request Method = [" + request.getMethod() + "], ");
sb.append("Request URL Path = [" + request.getRequestURL() + "], ");
String headers =
Collections.list(request.getHeaderNames()).stream()
.map(headerName -> headerName + " : " + Collections.list(request.getHeaders(headerName)) )
.collect(Collectors.joining(", "));
if (headers.isEmpty()) {
sb.append("Request headers: NONE,");
} else {
sb.append("Request headers: ["+headers+"],");
}
String parameters =
Collections.list(request.getParameterNames()).stream()
.map(p -> p + " : " + Arrays.asList( request.getParameterValues(p)) )
.collect(Collectors.joining(", "));
if (parameters.isEmpty()) {
sb.append("Request parameters: NONE.");
} else {
sb.append("Request parameters: [" + parameters + "].");
}
return sb.toString();
}
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