是否有更快/更好的leettime方式？

Question

我通过推特发现了leettime,它的新颖性足以让我想要搞砸它/与你们分享.让我感到沮丧的是这个版本不会做几秒钟.似乎可能有更有效的方式来产生时间,你怎么看？

Leet时间

现在,这个leettime是如何计算的？

对于给定的人工时间(例如,上午11:15),leettime的值对应于您必须累加13小时37分钟才能准确达到此时间的次数.每当结果在计算过程中溢出时(即获得的时间超过23:59时),您将减去24小时以保持时钟.

例:

00:00的leettime为0,13:37的leettime为1,leettime 2对应于03:14 am(因为13:37加上13小时37分钟是03:14).

白天每个人的时间都有独特的leettime吗？

是! 正好有24*60 = 1440个不同的leettimes,每个对应于一天中的一分钟.

添加你认为很酷的其他东西,我相信这个人会喜欢它.

我把PHP版本搞定,认为它是最容易访问和便携的.其他版本可在此处获得.

<?php
/**
 * Converts standard time to leettime.
 * 
 * @param int h the hour in standard time
 * @param int m the minute in standard time
 * 
 * @return int the leettime or -1 if the input
 *         parameters are invalid
 */
function TimeToLeet($h, $m){
  if(!is_numeric($h) || !is_numeric($m) ||
    $h > 23 || $h < 0 || $m > 59 || $m < 0)
      return -1;

  $curm = 0;
  $curh = 0;
  $i = 0;
  while ($curm != $m || ($curh % 24) != $h){  
    if($curm < 23){
      $curh += 13;
      $curm += 37;      
    } else {
      $curh += 14;
      $curm -= 23;      
    }
    ++$i;
  }
  return $i;  
}

/**
 * Converts leettime to standard time.
 * 
 * @param int leet the time in leettime-format in the
 *        range from 0 - 1439
 * 
 * @return var an int-Array with the hours at position 0
 * and minutes at position 1 (-1 if the input parameter
 * is not in range)
 */
function LeetToTime($leet){
  if($leet > 1439 || $leet < 0) return array(-1, -1);
  $m = $leet * 37;
  $h = ($leet * 13) + ($m / 60);
  return array($h % 24, $m % 60);
}

// Demonstrate usage

$h = (int)date("G");
$m = (int)date("i");

echo date("H:i")." = ".TimeToLeet($h,$m);

echo "
";

$leettime = 999;
$result = LeetToTime($leettime);
if($result[0] == -1) echo "error";
else {
  $h = $result[0];
  $m = $result[1];
  echo $leettime." = ".($h>9?$h:"0".$h) . 
    ":".($m>9?$m:"0".$m);
}
?>

Answer 1

要快速从HH:MM转换为Leet,请尝试使用Modular Arithmetic:

首先,将13:37转换为数字mod 1440; 具体而言,13*60 + 37 = 817

找到817 mod 1440的倒数.结果是913(从Wolfram Alpha窃取).913具有913*817 == 1 mod 1440的属性.

或者,如果你想使用13分37秒; 你会工作mod 86400,和817 ^ -1 == 67153.

将目标时间转换为数字mod 1440; 然后乘以913 mod 1440得到相应的leet时间.要转换回来,乘以817.

例:

Going from leet time to normal time (accuracy to the minute):
someLeetTime = 1337
//where 817 = 13*60 + 37 = 13:37 in minutes
timeInMinutes = someLeetTime * 817 mod 1440 = 809
hours = timeInMinutes / 60 = 13
minutes = timeInMinutes % 60 = 29

Going from normal time to leet time (accuracy to the minute):
hours = 13
minutes = 29
timeInMinutes = hours * 60 + minutes = 809
//913 = 817^-1 mod 1440
someLeetTime = timeInMinutes * 913 mod 1440 = 1337 
13:29 is 1337 leet time  

并且,一个可能的实施秒,在13:37被视为13分37秒.(技术上违反了标准,但我们是3333,并且可以做到这一点)

Going from leet time to normal time (accuracy to the second):
someLeetTime = 1337
//where 817 = 13*60 + 37 = 13:37 in seconds
timeInSeconds = someLeetTime * 817 mod 86400 = 55529
hours = timeInSeconds / 3600 = 15
minutes = (timeInSeconds % 3600) / 60 = 25
seconds = timeInSeconds % 60 = 29

1337 in the new system is 15:25:29

Going from normal time to leet time (accuracy to the second):
hours = 15
minutes = 25
seconds = 29
timeInSeconds = hours * 3600 + minutes*60 + seconds = 55529
//67153 = 817^-1 mod 86400
someLeetTime = timeInSeconds * 67153 mod 86400 = 1337 
15:25:29 is 1337 leet time  

谢谢Crypto和Modular Arithmetic.

为了推动这个伟大的事业,我建造了一个时钟! 嗯......实际上是6.