Tie*_*rcq 2 c# linq linq-to-xml
如何将xml元素导入对象?我下面的代码不起作用,它在SetValue失败,我无法弄清楚原因.
但即便如此,我怀疑linq有一个更清洁的方式,但我找不到任何例子.
class Printers {
public List<Printer> list = new List<Printer>();
public Printers()
{
var xDoc = XDocument.Load(Properties.Settings.Default.XmlSetupPath).Root;
var xPrinters = xDoc.Element("printers").Elements();
foreach (var xPrinter in xPrinters)
{
var printer = new Printer();
foreach (var xEl in xPrinter.Elements())
{
printer.GetType().GetProperty(xEl.Name.ToString()).SetValue(printer, xEl.Value);
}
}
}
}
class Printer
{
public string name;
public string ip;
public string model;
public string infx86;
public string infx64;
public string location;
public string comment;
}
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我的XML:
<printers>
<printer>
<name>my Printer</name>
<ip>192.168.100.100</ip>
<model>Brother</model>
<driver>ab</driver>
<infx86>ab\cd.INF</infx86>
<comment>Copycenter</comment>
</printer>
<printer>
<name>my Printer</name>
<foobar>oh no!</foobar>
</printer>
</printers>
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我想要
你要的是属性 - 但你的类型只有字段.要么创建属性,如下所示:
public string name { get; set; }
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......或者Type.GetField
改为使用.
为了让它更漂亮,我个人会FromXElement
为你的Printer
班级添加一个静态方法,此时你可以:
list = xDoc.Element("printers")
.Elements()
.Select(Printer.FromXElement)
.ToList();
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或者您可以编写一个通用方法来创建一个新实例并通过反射填充它,例如
public static T FromXElement<T>(XElement element) where T : class, new()
{
T value = new T();
foreach (var subElement in element.Elements())
{
var field = typeof(T).GetField(subElement.Name.LocalName);
field.SetValue(value, (string) subElement);
}
return value;
}
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然后:
list = xDoc.Element("printers")
.Elements()
.Select(XmlReflection.FromXElement<Printer>)
.ToList();
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