Igo*_*syn 2 c++ arrays random loops
我遇到了一个我最初认为很容易解决的问题!
我有一个包含4个值的枚举(空,男,女,小).我有一个对应50个座位的阵列.所以,我想根据随机生成的座位号码将男人,女人和孩子放在空座位上.如果座位不为空,则程序应继续搜索其他空座位.
这就是我所拥有的:
#include <cstdlib>
#include <ctime>
#include <iostream>
#include <string>
using namespace std;
enum pax {E, M, F, C};
pax seats[50] = {E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E,
E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E, E};
int paxNumMaleTotal; // Total number of Male passengers Loaded
int paxNumFemaleTotal;
int paxNumChildTotal;
void random(int j);
int main() {
// Randomize seating for Male
int n=1;
int i=0;
paxNumMaleTotal=35;
paxNumFemaleTotal=8;
paxNumChildTotal=5;
while (n<= paxNumMaleTotal) { // loop until all men take their seats
while (seats[i] != M || seats[i] != F || seats[i] != C) {
// take a seat unless the seat is not occupied
random(i); // generate a random seat to be taken
seats[i] = M; // Seat is taken by a man
}
n++; // seat is taken, take the next one
}
for (int k=0; k<50; k++) { // printing the seating chart
cout << seats[k] << endl;
}
}
void random(int j) // this is the function that gives a random seat number
{
srand( time( NULL ) );
j = rand() % 50;
}
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所以,我尝试了所有可能的选择.它要么将男性放在所有50个座位中,要么就像在这种情况下将男性放在第一个座位而没有循环.非常感谢你的时间!
谢谢你的帮助.使用参考,我解决了随机选择座位的问题.循环问题仍然存在.它只选择一个座位(随机)而不是35个座位.:-(
编辑:谢谢!random_shuffle函数起到了作用!
for (int i=0; i < paxNumMaleTotal; i++) {
seats[i] = M;
}
for (int i = paxNumMaleTotal; i < paxNumFemaleTotal + paxNumMaleTotal; i++) {
seats[i] = F;
}
for (int i=paxNumFemaleTotal + paxNumMaleTotal; i < paxNumFemaleTotal + paxNumMaleTotal +
paxNumChildTotal; i++) {
seats[i] = C;
}
// Randomize seating for passengers
std::random_shuffle (&seats[0], &seats[49]);
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这个:
srand( time( NULL ) );
j = rand() % 50;
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是问题.time(NULL)具有1秒的分辨率.这使你的随机生成器几乎总是相同的值,因为外循环比一秒快得多.
解决方案:在程序开头只初始化一次随机生成器.
另外:你的任命j
不起作用.您修改副本的说法,并再也没有回到这个副本.
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