roc*_*kit 13 sql union distinct distinct-values
我试图使用union来获取2个表中的所有不同值.
我们的想法是获得columnA列中所有唯一值的计数而不重复,这样我就可以得到包含唯一columnA的所有列的总和.
这是我试过的(sql server express 2008)
select
count(Distinct ColumnA)
from
(
select Distinct ColumnA as ColumnA from tableX where x = y
union
select Distinct ColumnA as ColumnA from tableY where y=z
)
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Jim*_*agg 21
SELECT COUNT(distinct tmp.ColumnA) FROM ( (SELECT ColumnA FROM TableX WHERE x=y)
UNION (SELECT ColumnA FROM TableY WHERE y=z) ) as tmp
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TableX和TableY的额外区别不是必需的; 它们将被删除在tmp.ColumnA子句中.声明临时表应该消除可能阻止查询执行的歧义.
Ada*_*Dev 15
SELECT COUNT(*)
FROM
(
SELECT DISTINCT ColumnA From TableX WHERE x = y
UNION
SELECT DISTINCT ColumnA From TableY WHERE y = z
) t
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使用"UNION"不会返回重复项.如果您使用"UNION ALL",那么将返回每个表的重复ColumnA值.