那些遇到过的问题

计算两个坐标之间距离的函数

Eri*_*rik 109 javascript distance coordinates

我目前正在使用下面的功能,但它无法正常工作.根据谷歌地图,这些坐标(从59.3293371,13.4877472到59.3225525,13.4619422)之间的距离是2.2公里,而函数返回1.6公里.如何使此功能返回正确的距离？

function getDistanceFromLatLonInKm(lat1, lon1, lat2, lon2) {
  var R = 6371; // Radius of the earth in km
  var dLat = deg2rad(lat2-lat1);  // deg2rad below
  var dLon = deg2rad(lon2-lon1); 
  var a = 
    Math.sin(dLat/2) * Math.sin(dLat/2) +
    Math.cos(deg2rad(lat1)) * Math.cos(deg2rad(lat2)) * 
    Math.sin(dLon/2) * Math.sin(dLon/2)
    ; 
  var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a)); 
  var d = R * c; // Distance in km
  return d;
}

function deg2rad(deg) {
  return deg * (Math.PI/180)
}
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jsFiddle:http://jsfiddle.net/edgren/gAHJB/

Eth*_*own 145

你正在使用的是所谓的半正式公式,它计算了乌鸦飞行时球体上两点之间的距离.您提供的Google地图链接显示距离为2.2 km,因为它不是直线.

Wolphram Alpha是进行地理计算的绝佳资源,同时显示这两点之间的距离为1.652 km.

行驶距离与直线距离(红线矿).

如果你正在寻找直线距离(作为乌鸦文件),你的功能正常.如果您想要的是驾驶距离(或骑车距离或公共交通距离或步行距离),您必须使用地图API(Google或Bing是最受欢迎的)来获得适当的路线,其中包括距离.

顺便提一下,Google Maps API在其google.maps.geometry.spherical命名空间(查找computeDistanceBetween)中提供了球形距离的打包方法.它可能比滚动你自己更好(对于初学者,它使用更精确的地球半径值).

对于我们中间的挑剔,当我说"直线距离"时,我指的是"球体上的直线",当然,它实际上是一条曲线(即大圆距离).

  • 这是一个很好的答案.我说很漂亮,因为所提供的细节对于理解差异来说太好了,即使像我这样的新手也是如此. (3认同)
  • 所以这就是为什么!非常感谢你的回答:) (2认同)
  • 我的荣幸!回答很有趣. (2认同)

Der*_*rek 57

我之前写了一个类似的方程式 - 经过测试,也达到了1.6公里.

你的谷歌地图显示了驾驶距离.

你的功能正在计算乌鸦飞行(直线距离).

alert(calcCrow(59.3293371,13.4877472,59.3225525,13.4619422).toFixed(1));



    //This function takes in latitude and longitude of two location and returns the distance between them as the crow flies (in km)
    function calcCrow(lat1, lon1, lat2, lon2) 
    {
      var R = 6371; // km
      var dLat = toRad(lat2-lat1);
      var dLon = toRad(lon2-lon1);
      var lat1 = toRad(lat1);
      var lat2 = toRad(lat2);

      var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
        Math.sin(dLon/2) * Math.sin(dLon/2) * Math.cos(lat1) * Math.cos(lat2); 
      var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a)); 
      var d = R * c;
      return d;
    }

    // Converts numeric degrees to radians
    function toRad(Value) 
    {
        return Value * Math.PI / 180;
    }
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  • 我认为您的变量名太具有描述性了：） (3认同)

Tij*_*ens 14

更新：我创建了一个实现以下算法的 npm 包：https://www.npmjs.com/package/calculate-distance- Between-coordinates

我在 typescript 和 ES6 中实现了这个算法

export type Coordinate = {
  lat: number;
  lon: number;
};
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获取两点之间的距离：

function getDistanceBetweenTwoPoints(cord1: Coordinate, cord2: Coordinate) {
  if (cord1.lat == cord2.lat && cord1.lon == cord2.lon) {
    return 0;
  }

  const radlat1 = (Math.PI * cord1.lat) / 180;
  const radlat2 = (Math.PI * cord2.lat) / 180;

  const theta = cord1.lon - cord2.lon;
  const radtheta = (Math.PI * theta) / 180;

  let dist =
    Math.sin(radlat1) * Math.sin(radlat2) +
    Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);

  if (dist > 1) {
    dist = 1;
  }

  dist = Math.acos(dist);
  dist = (dist * 180) / Math.PI;
  dist = dist * 60 * 1.1515;
  dist = dist * 1.609344; //convert miles to km
  
  return dist;
}
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获取坐标数组之间的距离

export function getTotalDistance(coordinates: Coordinate[]) {
  coordinates = coordinates.filter((cord) => {
    if (cord.lat && cord.lon) {
      return true;
    }
  });
  
  let totalDistance = 0;

  if (!coordinates) {
    return 0;
  }

  if (coordinates.length < 2) {
    return 0;
  }

  for (let i = 0; i < coordinates.length - 2; i++) {
    if (
      !coordinates[i].lon ||
      !coordinates[i].lat ||
      !coordinates[i + 1].lon ||
      !coordinates[i + 1].lat
    ) {
      totalDistance = totalDistance;
    }
    totalDistance =
      totalDistance +
      getDistanceBetweenTwoPoints(coordinates[i], coordinates[i + 1]);
  }

  return totalDistance.toFixed(2);
}
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Beh*_*zad 11

Derek的解决方案对我来说很好,我只是简单地将其转换为PHP,希望它可以帮助那里的人!

function calcCrow($lat1, $lon1, $lat2, $lon2){
        $R = 6371; // km
        $dLat = toRad($lat2-$lat1);
        $dLon = toRad($lon2-$lon1);
        $lat1 = toRad($lat1);
        $lat2 = toRad($lat2);

        $a = sin($dLat/2) * sin($dLat/2) +sin($dLon/2) * sin($dLon/2) * cos($lat1) * cos($lat2); 
        $c = 2 * atan2(sqrt($a), sqrt(1-$a)); 
        $d = $R * $c;
        return $d;
}

// Converts numeric degrees to radians
function toRad($Value) 
{
    return $Value * pi() / 180;
}
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Sai*_*pta 11

使用Haversine公式，代码来源：

//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::
//:::                                                                         :::
//:::  This routine calculates the distance between two points (given the     :::
//:::  latitude/longitude of those points). It is being used to calculate     :::
//:::  the distance between two locations using GeoDataSource (TM) prodducts  :::
//:::                                                                         :::
//:::  Definitions:                                                           :::
//:::    South latitudes are negative, east longitudes are positive           :::
//:::                                                                         :::
//:::  Passed to function:                                                    :::
//:::    lat1, lon1 = Latitude and Longitude of point 1 (in decimal degrees)  :::
//:::    lat2, lon2 = Latitude and Longitude of point 2 (in decimal degrees)  :::
//:::    unit = the unit you desire for results                               :::
//:::           where: 'M' is statute miles (default)                         :::
//:::                  'K' is kilometers                                      :::
//:::                  'N' is nautical miles                                  :::
//:::                                                                         :::
//:::  Worldwide cities and other features databases with latitude longitude  :::
//:::  are available at https://www.geodatasource.com                         :::
//:::                                                                         :::
//:::  For enquiries, please contact sales@geodatasource.com                  :::
//:::                                                                         :::
//:::  Official Web site: https://www.geodatasource.com                       :::
//:::                                                                         :::
//:::               GeoDataSource.com (C) All Rights Reserved 2018            :::
//:::                                                                         :::
//:::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::

function distance(lat1, lon1, lat2, lon2, unit) {
    if ((lat1 == lat2) && (lon1 == lon2)) {
        return 0;
    }
    else {
        var radlat1 = Math.PI * lat1/180;
        var radlat2 = Math.PI * lat2/180;
        var theta = lon1-lon2;
        var radtheta = Math.PI * theta/180;
        var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
        if (dist > 1) {
            dist = 1;
        }
        dist = Math.acos(dist);
        dist = dist * 180/Math.PI;
        dist = dist * 60 * 1.1515;
        if (unit=="K") { dist = dist * 1.609344 }
        if (unit=="N") { dist = dist * 0.8684 }
        return dist;
    }
}
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示例代码在 LGPLv3 下获得许可。

Nic*_*ith 6

为 Node.JS 用户添加这个。您可以使用该haversine-distance模块来执行此操作，因此您无需自行处理计算。有关更多信息，请参阅npm 页面。

安装：

npm install --save hasrsine-distance

您可以按如下方式使用该模块：

var haversine = require("haversine-distance");

//First point in your haversine calculation
var point1 = { lat: 6.1754, lng: 106.8272 }

//Second point in your haversine calculation
var point2 = { lat: 6.1352, lng: 106.8133 }

var haversine_m = haversine(point1, point2); //Results in meters (default)
var haversine_km = haversine_m /1000; //Results in kilometers

console.log("distance (in meters): " + haversine_m + "m");
console.log("distance (in kilometers): " + haversine_km + "km");
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Noo*_*rul 5

试试这个.它在VB.net中,您需要将其转换为Javascript.此函数接受十进制分钟的参数.

    Private Function calculateDistance(ByVal long1 As String, ByVal lat1 As String, ByVal long2 As String, ByVal lat2 As String) As Double
    long1 = Double.Parse(long1)
    lat1 = Double.Parse(lat1)
    long2 = Double.Parse(long2)
    lat2 = Double.Parse(lat2)

    'conversion to radian
    lat1 = (lat1 * 2.0 * Math.PI) / 60.0 / 360.0
    long1 = (long1 * 2.0 * Math.PI) / 60.0 / 360.0
    lat2 = (lat2 * 2.0 * Math.PI) / 60.0 / 360.0
    long2 = (long2 * 2.0 * Math.PI) / 60.0 / 360.0

    ' use to different earth axis length
    Dim a As Double = 6378137.0        ' Earth Major Axis (WGS84)
    Dim b As Double = 6356752.3142     ' Minor Axis
    Dim f As Double = (a - b) / a        ' "Flattening"
    Dim e As Double = 2.0 * f - f * f      ' "Eccentricity"

    Dim beta As Double = (a / Math.Sqrt(1.0 - e * Math.Sin(lat1) * Math.Sin(lat1)))
    Dim cos As Double = Math.Cos(lat1)
    Dim x As Double = beta * cos * Math.Cos(long1)
    Dim y As Double = beta * cos * Math.Sin(long1)
    Dim z As Double = beta * (1 - e) * Math.Sin(lat1)

    beta = (a / Math.Sqrt(1.0 - e * Math.Sin(lat2) * Math.Sin(lat2)))
    cos = Math.Cos(lat2)
    x -= (beta * cos * Math.Cos(long2))
    y -= (beta * cos * Math.Sin(long2))
    z -= (beta * (1 - e) * Math.Sin(lat2))

    Return Math.Sqrt((x * x) + (y * y) + (z * z))
End Function
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编辑 javascript中的转换函数

function calculateDistance(lat1, long1, lat2, long2)
  {    

      //radians
      lat1 = (lat1 * 2.0 * Math.PI) / 60.0 / 360.0;      
      long1 = (long1 * 2.0 * Math.PI) / 60.0 / 360.0;    
      lat2 = (lat2 * 2.0 * Math.PI) / 60.0 / 360.0;   
      long2 = (long2 * 2.0 * Math.PI) / 60.0 / 360.0;       


      // use to different earth axis length    
      var a = 6378137.0;        // Earth Major Axis (WGS84)    
      var b = 6356752.3142;     // Minor Axis    
      var f = (a-b) / a;        // "Flattening"    
      var e = 2.0*f - f*f;      // "Eccentricity"      

      var beta = (a / Math.sqrt( 1.0 - e * Math.sin( lat1 ) * Math.sin( lat1 )));    
      var cos = Math.cos( lat1 );    
      var x = beta * cos * Math.cos( long1 );    
      var y = beta * cos * Math.sin( long1 );    
      var z = beta * ( 1 - e ) * Math.sin( lat1 );      

      beta = ( a / Math.sqrt( 1.0 -  e * Math.sin( lat2 ) * Math.sin( lat2 )));    
      cos = Math.cos( lat2 );   
      x -= (beta * cos * Math.cos( long2 ));    
      y -= (beta * cos * Math.sin( long2 ));    
      z -= (beta * (1 - e) * Math.sin( lat2 ));       

      return (Math.sqrt( (x*x) + (y*y) + (z*z) )/1000);  
    }
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  • 这个问题问了的JavaScript的答案.. 你必须把它转换成英文:) (5认同)
  • 添加了一个javascript版本 (2认同)
  • 尝试为变量使用更有意义的名称。不要害怕变得冗长，因为现在 javascript 通常被缩小，变量名称就变得只对人类有用。例如： `const EarthsMajorAccess = 6378137.0;` 消除了对有用注释的需要（因为变量名称暗示了它是什么） (2认同)

小智 5

在javascript中计算两点之间的距离

function distance(lat1, lon1, lat2, lon2, unit) {
        var radlat1 = Math.PI * lat1/180
        var radlat2 = Math.PI * lat2/180
        var theta = lon1-lon2
        var radtheta = Math.PI * theta/180
        var dist = Math.sin(radlat1) * Math.sin(radlat2) + Math.cos(radlat1) * Math.cos(radlat2) * Math.cos(radtheta);
        dist = Math.acos(dist)
        dist = dist * 180/Math.PI
        dist = dist * 60 * 1.1515
        if (unit=="K") { dist = dist * 1.609344 }
        if (unit=="N") { dist = dist * 0.8684 }
        return dist
}
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有关更多详细信息，请参阅：参考链接

Art*_*újo 5

您也可以使用模块：

\n

安装：

\n
$ npm install geolib\n
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用法：

\n
import { getDistance } from \'geolib\'\n\nconst distance = getDistance(\n    { latitude: 51.5103, longitude: 7.49347 },\n    { latitude: "51\xc2\xb0 31\' N", longitude: "7\xc2\xb0 28\' E" }\n)\n\nconsole.log(distance)\n
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文档： https: //www.npmjs.com/package/geolib

\n

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