当返回类型是ActionResult时,如何对操作进行单元测试?

Abh*_*eet 37 c# tdd unit-testing asp.net-mvc-4

我已经为下面的行动编写了单元测试.

[HttpPost]
public ActionResult/*ViewResult*/ Create(MyViewModel vm)
{
    if (ModelState.IsValid)
    {
        //Do something...
        return RedirectToAction("Index");
    }

    return View(vm);
}
Run Code Online (Sandbox Code Playgroud)

测试方法Model只有在返回类型时才能访问属性ViewResult.在上面的代码中,我已经使用RedirectToAction过这种动作的返回类型不能ViewResult.

在这种情况下,您如何对一个动作进行单元测试?

Pét*_*ter 71

所以这是我的小例子:

public ActionResult Index(int id)
{
  if (1 != id)
  {
    return RedirectToAction("asd");
  }
  return View();
}
Run Code Online (Sandbox Code Playgroud)

测试:

[TestMethod]
public void TestMethod1()
{
  HomeController homeController = new HomeController();
  ActionResult result = homeController.Index(10);
  Assert.IsInstanceOfType(result,typeof(RedirectToRouteResult));
  RedirectToRouteResult routeResult = result as RedirectToRouteResult;
  Assert.AreEqual(routeResult.RouteValues["action"], "asd");
}

[TestMethod]
public void TestMethod2()
{
  HomeController homeController = new HomeController();
  ActionResult result = homeController.Index(1);
  Assert.IsInstanceOfType(result, typeof(ViewResult));
}
Run Code Online (Sandbox Code Playgroud)

编辑:
一旦您确认结果类型是ViewResut,您可以转换为它:

ViewResult vResult = result as ViewResult;
if(vResult != null)
{
  Assert.IsInstanceOfType(vResult.Model, typeof(YourModelType));
  YourModelType model = vResult.Model as YourModelType;
  if(model != null)
  {
    //...
  }
}
Run Code Online (Sandbox Code Playgroud)


小智 10

请注意

Assert.IsInstanceOfType(result,typeof(RedirectToRouteResult)); 
Run Code Online (Sandbox Code Playgroud)

已被弃用.

新的语法是

Assert.That(result, Is.InstanceOf<RedirectToRouteResult>());
Run Code Online (Sandbox Code Playgroud)

  • 资源?看起来像Assert,这不是基本单元测试的一部分。https://msdn.microsoft.com/zh-CN/library/microsoft.visualstudio.testtools.unittesting.assert.aspx您是否在考虑使用nunit? (2认同)