布局中的Qt状态机转换

Question

好吧,我正在开发一个Qt应用程序,我想使用Qt State Framework来制作一些动画.

第一: 如何使用状态转换将水平布局中包含的一组按钮设置为另一个垂直布局？

第二: 如何在状态下显示小部件？例如菜单:当用户单击菜单中的按钮时,显示小部件(之前已使用widget-> hide()隐藏)... ???

这是一个代码示例:

boxInsert = new BoxInsert(this);
boxInsert->hide ();


btn1 = new QPushButton("Introducir", this);
btn2 = new QPushButton("Informe", this);
btn3 = new QPushButton("Salir", this);

QStateMachine *machine = new QStateMachine(this);

QState *st1 = new QState(machine);
st1->setObjectName ("menuMode");
st1->assignProperty (btn1, "pos", QPointF(center - btn1->width () / 2, 20));
st1->assignProperty (btn2, "pos", QPointF(center - btn1->width () / 2, 40));
st1->assignProperty (btn3, "pos", QPointF(center - btn1->width () / 2, 60));
st1->assignProperty (boxInsert, "visible", QVariant(false));

QState *st2 = new QState(machine);
st2->setObjectName ("barMode");
st2->assignProperty (btn1, "pos", QPointF(40, 0));
st2->assignProperty (btn2, "pos", QPointF(40, 0));
st2->assignProperty (btn3, "pos", QPointF(40, 0));
st1->assignProperty (boxInsert, "visible", QVariant(true));

machine->setInitialState (st1);

QAbstractTransition *t1 = st1->addTransition (btn1, SIGNAL(clicked()), st2);
//QSequentialAnimationGroup *sq1 = new QSequentialAnimationGroup;
//sq1->addPause (250);
t1->addAnimation (new QPropertyAnimation(btn1, "pos"));
t1->addAnimation (new QPropertyAnimation(btn2, "pos"));
t1->addAnimation (new QPropertyAnimation(btn3, "pos"));
t1->addAnimation (new QPropertyAnimation(boxInsert, "visible"));

machine->start ();

Answer 1

这就像当您启动机器时，它会改变按钮的颜色，这可能表明该按钮已被单击，然后执行与您的信号链接的操作，以便执行其链接的插槽。

s0->addTransition(s1);
s1->assignProperty(ui->pushButton,"styleSheet","background-color:rgb(255,0,0);");
s1->addTransition(s2);
s2->addTransition(ui->pushButton,SIGNAL(clicked()),s0);
QStateMachine m;
m.addState(s0);
m.addState(s1);
m.addState(s2);
m.setInitialState(s0);

要使小部件可见，请添加如下状态转换：

s1->assignProperty(MyWid,"visible", true);

并在 s0 中添加状态 s1 的转换。