我有一个函数,通过输出参数返回两个参数作为匿名复合类型.
我可以使用如下查询访问各个列:
# select * from guess_user('Joe','Bloggs');
confidence | matchid
------------+---------
0.142857 | 1121
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现在我想将此函数的输出与一些数据结合起来:
# select firstname,lastname from users limit 5;
firstname | lastname
-----------+----------
Adam | Smith
Amy | Peters
Annette | Bloggs
Annie | Mills
Amanda | Hibbins
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我正在寻找一个将输出以下内容的查询:
firstname | lastname | confidence | matchid
-----------+----------+------------+---------
Adam | Smith | |
Amy | Peters | |
Annette | Bloggs | |
Annie | Mills | |
Amanda | Hibbins | |
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使用调用guess_user的结果填充置信度和匹配列,并使用该行中的名称.
我目前最近的努力是:
# select firstname, lastname, guess_user(firstname, lastname) from users limit 5;
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哪个回报:
firstname | lastname | guess_user
-----------+-----------+---------------
Angela | Abbott | (0.285714,3)
Amy | Allan | (0.285714,4)
Annette | Allison | (0.285714,5)
Annie | Ashworth | (0.285714,6)
Amanda | Baird | (0.285714,7)
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有没有办法将guess_user输出拆分为单独的列?
Eme*_*ski 10
结合depesz和fazal的答案,这似乎工作:
select firstname, lastname, (guess_user(firstname, lastname)).*
from users
limit 5
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