分离postgres函数返回的记录

sim*_*ins 8 sql postgresql

我有一个函数,通过输出参数返回两个参数作为匿名复合类型.

我可以使用如下查询访问各个列:

# select * from guess_user('Joe','Bloggs');
 confidence | matchid 
------------+---------
   0.142857 |    1121
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现在我想将此函数的输出与一些数据结合起来:

# select firstname,lastname from users limit 5;
 firstname | lastname 
-----------+----------
 Adam      | Smith
 Amy       | Peters
 Annette   | Bloggs
 Annie     | Mills
 Amanda    | Hibbins
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我正在寻找一个将输出以下内容的查询:

 firstname | lastname | confidence | matchid 
-----------+----------+------------+---------
 Adam      | Smith    |            | 
 Amy       | Peters   |            | 
 Annette   | Bloggs   |            | 
 Annie     | Mills    |            | 
 Amanda    | Hibbins  |            | 
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使用调用guess_user的结果填充置信度和匹配列,并使用该行中的名称.

我目前最近的努力是:

# select firstname, lastname, guess_user(firstname, lastname) from users limit 5;
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哪个回报:

 firstname | lastname  |  guess_user   
-----------+-----------+---------------
 Angela    | Abbott    | (0.285714,3)
 Amy       | Allan     | (0.285714,4)
 Annette   | Allison   | (0.285714,5)
 Annie     | Ashworth  | (0.285714,6)
 Amanda    | Baird     | (0.285714,7)
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有没有办法将guess_user输出拆分为单独的列?

Eme*_*ski 10

结合depesz和fazal的答案,这似乎工作:

select firstname, lastname, (guess_user(firstname, lastname)).*
from users
limit 5
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