在.bat文件中获取图像文件尺寸

Question

我有一个bat文件,列出代码所在文件夹中所有图像的路径

@echo off
break > infofile.txt
for /f "delims=" %%F in ('dir /b /s *.bmp') do (
   echo %%F 1 1 1 100 100 >>infofile.txt 
)

文本文件如下所示

C:\Users\Charles\Dropbox\trainer\temp\positive\rawdata\diags(1).bmp 1 1 1 100 100  
C:\Users\Charles\Dropbox\trainer\temp\positive\rawdata\diags(348).bmp 1 1 1 100 100  
C:\Users\Charles\Dropbox\trainer\temp\positive\rawdata\diags(353).bmp 1 1 1 100 100  

我想要做的是用每个图像宽度和高度的尺寸替换100 100.感谢提前.

Answer 1

你可以使用 MediaInfo:

@ECHO OFF &SETLOCAL
(for /r %%a in (*.jpg *.bmp *.png) do (
    set "width="
    set "height="
    for /f "tokens=1*delims=:" %%b in ('"MEDIAINFO --INFORM=Image;%%Width%%:%%Height%% "%%~a""') do (
        echo(%%~a 1 1 1 %%~b %%~c
    )
))>infofile.txt
type infofile.txt

输出示例:

C:\Users\Private\Pictures\snap001.png 1 1 1 528 384
C:\Users\Private\Pictures\snap002.png 1 1 1 1920 1080
C:\Users\Private\Pictures\snap003.png 1 1 1 617 316
C:\Users\Private\Pictures\snap004.png 1 1 1 1920 1080
C:\Users\Private\Pictures\snap005.png 1 1 1 514 346
C:\Users\Private\Pictures\snap006.png 1 1 1 1920 1080
C:\Users\Private\Pictures\snap007.png 1 1 1 395 429
C:\Users\Private\Pictures\snap008.png 1 1 1 768 566
C:\Users\Private\Pictures\snap009.png 1 1 1 1536 1080
C:\Users\Private\Pictures\snap010.png 1 1 1 1600 480