HTML表单PHP发布到自我以验证或提交到新页面

Question

HTML表单PHP发布到自我以验证或提交到新页面

前期道歉.今天是我使用php的第一天,我终于找到了如何让我的页面回复自己(我的页面为.html,而不是.php),但现在我无法弄清楚如何在验证表单后将数据带到新页面.我已经工作了很长一段时间,我很生气.这是一个简单的例子:

<!DOCTYPE HTML>
<html>
<head>
<style>
.error {color: #FF0000;}
</style>
</head>
<body>

<?php
// Initialize variables and set to empty strings
$firstName=$lastName="";
$firstNameErr=$lastNameErr="";

// Validate input and sanitize
if ($_SERVER['REQUEST_METHOD']== "POST") {
   if (empty($_POST["firstName"])) {
      $firstNameErr = "First name is required";
   }
   else {
      $firstName = test_input($_POST["firstName"]);
   }
   if (empty($_POST["lastName"])) {
      $lastNameErr = "Last name is required";
   }
   else {
      $lastName = test_input($_POST["lastName"]);
   }
}

// Sanitize data
function test_input($data) {
   $data = trim($data);
   $data = stripslashes($data);
   $data = htmlspecialchars($data);
   return $data;
}
?>

<h2>Find Customer</h2>
<p><span class="error">* required</span></p>
<form action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']);?>" method="post">
First Name: <input type="text" name="firstName" value="<?php echo $firstName; ?>"><span class="error">* <?php echo $firstNameErr; ?></span><br><br>
Last Name: <input type="text" name="lastName" value="<?php echo $lastName; ?>"><span class="error">* <?php echo $lastNameErr; ?><br><br>
<input type="submit">
</form>

</body>
</html>

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好.所以上面,你会看到表单回发给自己,所以它可以验证.好.现在,考虑到所有事情都是有效的,我如何发布到另一个脚本(action ="otherAction.php",也许？),以便实际处理数据？

此外,任何安全建议表示赞赏.我尽力将安全考虑在内.谢谢.

Answer 1

Dri*_*eña 7

满足所有条件后即可使用 header('Location: http:mywebsite.com/otherAction.php')

// Validate input and sanitize
if ($_SERVER['REQUEST_METHOD']== "POST") {
   $valid = true; //Your indicator for your condition, actually it depends on what you need. I am just used to this method.

   if (empty($_POST["firstName"])) {
      $firstNameErr = "First name is required";
      $valid = false; //false
   }
   else {
      $firstName = test_input($_POST["firstName"]);
   }
   if (empty($_POST["lastName"])) {
      $lastNameErr = "Last name is required";
      $valid = false;
   }
   else {
      $lastName = test_input($_POST["lastName"]);
   }

  //if valid then redirect
  if($valid){
   header('Location: http://mywebsite.com/otherAction.php');
   exit();
  }
}

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在我的一些作品中,我的设置是这样的,但我在这里学到了一些不太好的东西.当您在提交表单后刷新页面时,POST值仍然存在并且可能会复制条目.哪个IMO不好.

注意,出于安全原因,您应该在重定向后立即使用`exit()`. (2认同)
@Jaikrat你在重定向时丢失了$ _POST ..有两种方法可以解决这个问题.1.)在cookie中存储id或2.)使用$ _GET在url中添加查询字符串,例如`mywebsite.com/page/page？用户ID = 12` (2认同)

Answer 2

Laz*_*zik 6

使用 javascript 进行验证，然后将帖子表单发送给自身或发送到可以处理数据的另一个页面。

<!DOCTYPE html>
<html>
<head>
<script>
function validateForm()
{
var x=document.forms["myForm"]["fname"].value;
if (x==null || x=="")
  {
  alert("First name must be filled out");
  return false;
  }
}
</script>
</head>

<body>
<form name="myForm" action="demo_form.php" onsubmit="return validateForm()" method="post">
First name: <input type="text" name="fname">
<input type="submit" value="Submit">
</form>
</body>

</html>

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来源： http: //www.w3schools.com/js/js_form_validation.asp

<!DOCTYPE HTML>
<html>
<head>
<style>
.error {color: #FF0000;}
</style>
</head>
<body>

<?php
// Initialize variables and set to empty strings
$firstName=$lastName="";
$firstNameErr=$lastNameErr="";

// Control variables
$app_state = "empty";  //empty, processed, logged in
$valid = 0;

// Validate input and sanitize
if ($_SERVER['REQUEST_METHOD']== "POST") {
   if (empty($_POST["firstName"])) {
      $firstNameErr = "First name is required";
   }
   else {
      $firstName = test_input($_POST["firstName"]);
      $valid++;
   }
   if (empty($_POST["lastName"])) {
      $lastNameErr = "Last name is required";
   }
   else {
      $lastName = test_input($_POST["lastName"]);
      $valid++;
   }

   if ($valid >= 2) {
      $app_state = "processed";
   }
}

// Sanitize data
function test_input($data) {
   $data = trim($data);
   $data = stripslashes($data);
   $data = htmlspecialchars($data);
   return $data;
}

if ($app_state == "empty") {
?>
<h2>Find Customer</h2>
<p><span class="error">* required</span></p>
<form action="<?php echo htmlspecialchars($_SERVER['PHP_SELF']);?>" method="post">
First Name: <input type="text" name="firstName" value="<?php echo $firstName; ?>"><span class="error">* <?php echo $firstNameErr; ?></span><br><br>
Last Name: <input type="text" name="lastName" value="<?php echo $lastName; ?>"><span class="error">* <?php echo $lastNameErr; ?><br><br>
<input type="submit">
</form>

</body>
</html>
<?php
}
elseif ($app_state == "processed") {
    if ($firstName == "Vincent") {
        $app_state = "Logged in";
    }
}

if ($app_state == "Logged in") {
    echo("Logged in<br> Hello Vincent</body></html>");
}
?>

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