如何在django中获取涉及多对多关系的对象列表

Atm*_*tma 10 django django-models django-orm

我有以下型号:

class Committee(models.Model):
    customer = models.ForeignKey(Customer, related_name="committees")
    name = models.CharField(max_length=255)
    members = models.ManyToManyField(member, through=CommitteeMember, related_name="committees")
    items = models.ManyToManyField(Item, related_name="committees", blank=True)

class CommitteeRole(models.Model):
    committee = models.ForeignKey('Committee')
    member = models.ForeignKey(member)
    #user is the members user/user number
    user = models.ForeignKey(User)
    role = models.IntegerField(choices=ROLES, default=0)

class Member(models.Model):
    customer = models.ForeignKey(Customer, related_name='members')
    name = models.CharField(max_length=255)

class Item(models.Model):
    customer = models.ForeignKey(Customer, related_name="items")
    name = models.CharField(max_length=255)

class Customer(models.Model):
    user = models.OneToOneField(User, related_name="customer")
    name = models.CharField(max_length=255)
Run Code Online (Sandbox Code Playgroud)

我需要获取所有属于用户通过其连接的所有委员会的项目CommitteeRole.

像这样的东西:

committee_relations = CommitteeRole.objects.filter(user=request.user)
item_list = Item.objects.filter(committees=committee_relations__committee)
Run Code Online (Sandbox Code Playgroud)

我怎么能做到这一点?

kar*_*ikr 16

实际上,你已经完成了它(几乎):

committee_relations = CommitteeRole.objects.filter(user=request.user).values_list('committee__pk', flat=True)
item_list = Item.objects.filter(committees__in=committee_relations)
Run Code Online (Sandbox Code Playgroud)

而且,如果您要查找单个查询,可以尝试以下方法:

items = Item.objects.filter(customer__committees__committeerole__user=request.user)
Run Code Online (Sandbox Code Playgroud)

文档在这里这里