PHP TWITTER bot使用api 1.1版和游标来关注/取消关注

Question

此代码应该只取消关注没有追踪的用户,但它取消了一些粉丝,无法弄清楚原因.

$oTwitter = new TwitterOAuth (...)

$aFollowing = $oTwitter->get('friends/ids');
$aFollowing = $aFollowing->ids;
$aFollowers = $oTwitter->get('followers/ids');
$aFollowers = $aFollowers->ids;

$i=1;
foreach( $aFollowing as $iFollowing )
{
$isFollowing = in_array( $iFollowing, $aFollowers );

echo "$iFollowing: ".( $isFollowing ? 'OK' : '!!!' )."<br/>";

if( !$isFollowing )
{
$parameters = array( 'user_id' => $iFollowing );
$status = $oTwitter->post('friendships/destroy', $parameters);
} if ($i++ === 100 ) break;
}

难道问题不是别的吗？

编辑:为这篇文章添加了自己的答案,其代码可以关注关注者并在Twitter上取消关注非关注者.

Answer 1

这可行,我想也许它可以帮助像我这样的新手.安迪琼斯的回答真的很有帮助.在这里使用了很多其他东西的伟大的图书馆.

  require_once 'twitteroauth.php';

 $oTwitter = new TwitterOAuth 
(   'YOUR_TWITTER_APP_CONSUMER_KEY',
'YOUR_TWITTER_APP_CONSUMER_SECRET',
'YOUR_TWITTER_APP_OAUTH_TOKEN',
'YOUR_TWITTER_APP_OAUTH_SECRET');

//带有游标的完全跟随阵列(跟随者> 5000)

$e = 1;
$cursor = -1;
$full_followers = array();
do {

$follows = $oTwitter->get("followers/ids.json?screen_name=yourusername&cursor=".$cursor);

$foll_array = (array)$follows;

  foreach ($foll_array['ids'] as $key => $val) {

        $full_followers[$e] = $val;
        $e++; 
  }
       $cursor = $follows->next_cursor;

  } while ($cursor > 0);
echo "Number of following:" .$e. "<br /><br />";

//带有游标的全友好阵列(以下> 5000)

$e = 1;
$cursor = -1;
$full_friends = array();
do {

  $follow = $oTwitter->get("friends/ids.json?screen_name=yourusername&cursor=".$cursor);
  $foll_array = (array)$follow;

  foreach ($foll_array['ids'] as $key => $val) {

        $full_friends[$e] = $val;
        $e++;
  }
      $cursor = $follow->next_cursor;

} while ($cursor > 0);

//如果我是以下用户而他不跟我回来,我不知道他

    $index = 1;
    $unfollow_total=0;
    foreach( $full_friends as $iFollow )
    {
    $isFollowing = in_array( $iFollow, $full_followers );

    echo "$iFollow: ".( $isFollowing ? 'OK' : '!!!' )."<br/>";
    $index++;
     if( !$isFollowing )
        {
        $parameters = array( 'user_id' => $iFollow );
        $status = $oTwitter->post('friendships/destroy', $parameters);
        $unfollow_total++;
        } if ($unfollow_total === 999) break;
    }

//如果用户跟随我而我不是,我跟着

$index = 1;
$follow_total = 0;

foreach( $full_followers as $heFollows )
{
$amFollowing = in_array( $heFollows, $full_friends );

echo "$heFollows: ".( $amFollowing ? 'OK' : '!!!' )."<br/>";
 $index++;
 if( !$amFollowing )
    {
    $parameters = array( 'user_id' => $heFollows );
    $status = $oTwitter->post('friendships/create', $parameters);
    $follow_total++;
    } if ($follow_total === 999) break;
}

echo 'Unfollowed:'.$unfollow_total.'<br />';
echo 'Followed:'.$follow_total.'<br />';

Answer 2

如果你的粉丝大于5000,那么$aFollowers = $oTwitter->get('followers/ids');只返回前5000个ID.按什么顺序？Twitter不保证任何订单,所以我们只是假设随机.

如果进行以下检查$isFollowing = in_array( $iFollowing, $aFollowers );,则该人$iFollowing可能会或可能不会在列表中,$aFollowers具体取决于Twitter如何将关注者返回给您.如果这个人在前5000,那么这将有效,如果他们在第一个5000之外,那么即使该人合法地关注你,检查也会失败.

您需要通过游标拉取所有关注者.查看游标/页面上的文档- 将帮助您.基本上你需要这样做.

$aFollowers = array();
$cursor = -1;
do {
  $follows = $oTwitter->get('followers/ids?cursor=' . $cursor);
  $aFollowers = array_merge($follows->ids, $aFollowers);
  $cursor = $follows->next_cursor;
} while ($cursor > 0);