Mar*_*ark 9 javascript performance dojo
从JavaScript对象数组中获取最大值和最小值的最佳方法是什么?
鉴于:
var a = [{x:1,y:0},{x:-1,y:10},{x:12,y:20},{x:61,y:10}];
var minX = Infinity, maxX = -Infinity;
for( var x in a ){
if( minX > a[x].x )
minX = a[x].x;
if( maxX < a[x].x )
maxX = a[x].x;
}
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似乎有点笨拙.是否有更优雅的方式,也许使用道场?
它不会更有效率,只是为了咧嘴笑:
var minX = Math.min.apply(Math, a.map(function(val) { return val.x; }));
var maxX = Math.max.apply(Math, a.map(function(val) { return val.x; }));
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或者如果你愿意有三行代码:
var xVals = a.map(function(val) { return val.x; });
var minX = Math.min.apply(Math, xVals);
var maxX = Math.max.apply(Math, xVals);
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小智 6
使用此示例
var lowest = Number.POSITIVE_INFINITY;
var highest = Number.NEGATIVE_INFINITY;
var tmp;
for (var i=myArray.length-1; i>=0; i--) {
tmp = myArray[i].Cost;
if (tmp < lowest) lowest = tmp;
if (tmp > highest) highest = tmp;
}
console.log(highest, lowest);
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