barplot x 轴标签,在单独的行中具有分层分组变量

Ada*_*ter 5 r bar-chart axis-labels

在 Excel 中,数据的组织方式如下:

                                              Bare NP                   Singular-Marked NP               Plural-Marked NP   
                                    BrP Speakers    AmE Speakers    BrP Speakers    AmE Speakers    BrP Speakers AmE Speakers
Plural Interpretation               0.005747126 0.006896552         0.194117647 0.124567474         0.872093023 0.985815603
Plural & Singular Interpretation    0.649425287 0.910344828         0.029411765 0.051903114         0.127906977 0.014184397
Singular Interpretation             0.344827586 0.082758621         0.776470588 0.823529412         0           0
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我能够生成如下所示的堆叠条形图:

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是否有一种简单的方法可以使用 重现将 x 轴划分为单独条件(“裸 NP”、“单数标记 NP”和“复数标记 NP”)的方式R

目前我能想到的只有这个:

pluralInterp <- c(0.005747126,0.006896552,0.194117647,0.124567474,0.872093023,0.985815603)

pluralAndSingInterp <- c(0.649425287,0.910344828,0.029411765,0.051903114,0.127906977,0.014184397)

singInterp <- c(0.344827586,0.082758621,0.776470588,0.823529412,0,0)

a  <- rbind(pluralInterp,pluralAndSingInterp,singInterp)

colnames(a) <- c("Bare NP ~ BrP Speakers",
                 "Bare NP ~ AmE Speakers",
                 "Singular-Marked NP ~ BrP Speakers",
                 "Singular-Marked NP ~ AmE Speakers",
                 "Plural-Marked NP ~ BrP Speakers",
                 "Plural-Marked NP ~ AmE Speakers"
                 )

barplot(a,
        col=c("blue","red","purple"),
        ylab="Frequency of Interpretation",
        xlab="Form of NP and Native Language",
        main="Frequency of BrP and AmE Interpretations of NPs in Neutral Environments"
        )
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产生下图:

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the*_*ail 4

对边距进行一些手动调整并调用axis()两次就可以实现这一目标。保存条形图bp <- barplot(...)可以保存每个条形的中点以供将来参考。

oldpar <-par(mar=c(7,5.1,4.1,2.1))

bp <- barplot(a,
        col=c("blue","red","purple"),
        ylab="Frequency of Interpretation",
        xlab="",
        main="Frequency of BrP and AmE Interpretations \n of NPs in Neutral Environments",
        axisnames=FALSE
       )
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然后,您可以使用存储的值bp来正确对齐事物。line=...您可以使用参数来对齐组和子组标签axis()

avgpts <- tapply(bp,rep(1:3,each=2),mean)
grps <- c("Bare NP","Singular-Marked NP","Plural-Marked NP")
subgrps <- c("BrP","AmE")
axis(1,at=bp,labels=rep(subgrps,3), cex.axis=0.7)
axis(1,at=avgpts,labels=grps, cex.axis=0.7,line=1.5,lwd=0)

title(xlab="Form of NP and Native Language",line=4.5)
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导致:

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