如何设置wxpython Grid顶部标题？

Question

当我用wxpython创建一个网格时,我得到顶部列标题为"A","B","C"......

import wx
import wx.grid as gridlib

########################################################################
class MyForm(wx.Frame):
    """"""

    #----------------------------------------------------------------------
    def __init__(self):
        """Constructor"""
        wx.Frame.__init__(self, parent=None, title="A Simple Grid")
        panel = wx.Panel(self)

        myGrid = gridlib.Grid(panel)
        myGrid.CreateGrid(12, 8)

        sizer = wx.BoxSizer(wx.VERTICAL)
        sizer.Add(myGrid, 1, wx.EXPAND)
        panel.SetSizer(sizer)

if __name__ == "__main__":
    app = wx.PySimpleApp()
    frame = MyForm().Show()
    app.MainLoop()

但是我想设置自定义列标题:

这该怎么做？

Answer 1

WxPython wiki告诉我们,每一行和每列如何都有自己的可设置标签(标题),它可以包含任何文本以及它自己的其他布局.

列标题由命令设置

SetColLabelValue(int col, const wxString& value)

将列号和所需的标签值作为参数.

本教程进一步说明,您案例中的完整示例代码将如下所示:

import wx
import wx.grid as gridlib

########################################################################
class MyForm(wx.Frame):
    """"""

    #----------------------------------------------------------------------
    def __init__(self):
        """Constructor"""
        wx.Frame.__init__(self, parent=None, title="A Simple Grid")
        panel = wx.Panel(self)

        myGrid = gridlib.Grid(panel)
        myGrid.CreateGrid(12, 8)
        myGrid.SetColLabelValue(0, "ID")
        myGrid.SetColLabelValue(1, "Name")
        myGrid.SetColLabelValue(2, "Lastname")
        myGrid.SetColLabelValue(3, "01-Jan-13")
        # etc. etc.


        sizer = wx.BoxSizer(wx.VERTICAL)
        sizer.Add(myGrid, 1, wx.EXPAND)
        panel.SetSizer(sizer)

if __name__ == "__main__":
    app = wx.PySimpleApp()
    frame = MyForm().Show()
    app.MainLoop()

当然,如果该日期是在飞行中初始化的,那么你必须从一个datetime对象中获取它,例如从你的代码中添加这些行(取自这篇文章):

# Add to imports
import datetime  

# fetch date and you can give this, not hard coded string value.
datetime.datetime.today()

要在您的标题上重复多年/次,请将以下内容视为有用:

from dateutil import rrule
from datetime import datetime, timedelta

now = datetime.now()
tenYearsLater = now + timedelta(years=10)

for dt in rrule.rrule(rrule.DAILY, dtstart=now, until=tenYearsLater):
    print dt

此处的代码源,而不是打印,相应地设置标签.此示例打印两个时间实例之间的每个日期.你需要dateutil在你的项目中.