Mr.*_*Boy 1 c++ stl visual-studio-2005
我试图改编它以打印出std::vector<std::wstring>使用std :: copy 的内容但我不明白该代码是如何工作得很好,并且不能让它编译.代码应该是什么?
我使用了Rob的例子,但它不起作用:
std::vector<std::wstring> keys = ...;
std::copy(keys.begin(), keys.end(), std::ostream_iterator<std::wstring>(std::wcout, " "));
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我收到错误:
1>error C2665: 'std::ostream_iterator<_Ty>::ostream_iterator' : none of the 2 overloads could convert all the argument types
1> with
1> [
1> _Ty=std::wstring
1> ]
1> C:\Program Files\Microsoft Visual Studio 8\VC\include\iterator(300): could be 'std::ostream_iterator<_Ty>::ostream_iterator(std::basic_ostream<_Elem,_Traits> &,const _Elem *)'
1> with
1> [
1> _Ty=std::wstring,
1> _Elem=char,
1> _Traits=std::char_traits<char>
1> ]
1> while trying to match the argument list '(std::wostream, const char [2])'
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它为什么告诉我_Elem=char何时使用wcout哪种类型wostream?
您必须使用wstring, wchar_t模板参数和wcout输出流:
std::copy(v.begin(),
v.end(),
std::ostream_iterator<std::wstring, wchar_t>(std::wcout, L"\n"));
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测试程序:
#include <vector>
#include <string>
#include <iostream>
#include <iterator>
int main () {
std::vector<std::wstring> v;
v.push_back(L"Hello");
v.push_back(L"World");
std::copy(v.begin(),
v.end(),
std::ostream_iterator<std::wstring, wchar_t>(std::wcout, L"\n"));
}
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