onk*_*kar 7 python django django-views
楷模
image_url = models.ImageField(upload_to="uploads/shows",blank=True,null=True)
我有image_url,我需要使用JSON对象解析它到我的Android应用程序.我只需要图像的URL(绝对/相对).
我试过了
image_url=myObj.file.url
image_url=myObj.image_url
onk*_*kar 13
The correct working solution as provided by @alecxe is
image_url =myObj.image_url.url