我有以下内容build.gradle:
task aoeu << {
println "**************************** during"
}
tasks.publish.dependsOn(aoeu)
tasks.publish.doFirst {
println "************************* before"
}
tasks.publish.doLast {
println "************************* after"
}
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它的输出是:
:aoeu
**************************** during
:publish
************************* before
************************* after
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但我真正需要的是''在'之前'和之后'之间'发生'.如何才能做到这一点?"发布"应该仅仅取决于"之前"吗?如果是这样,我怎样才能保证它在其他依赖项之前发生?
pep*_*uch 15
据我所知,你的代码应该可以正常运行,但事实并非如此.doFirst应该在执行阶段doLast(执行阶段)之前运行的配置阶段执行.BTW这段代码工作正常:
正如Peter Niederwiser在这里写的那样/sf/answers/644291161/ doFirst在执行阶段作为第一个语句(之前doLast)运行,所以你的代码工作正常.此示例将显示gradle构建中的执行顺序:
task publish {
println "(1) before (run in configuration phase)" // this will run before gradle dependencies
}
task aoeu << {
println "(2) during (run in execution phase as last statement)"
}
tasks.publish.dependsOn(aoeu)
tasks.publish.doLast {
println "(4) after (run in execution phase as last statement)"
}
tasks.publish.doFirst {
println "(3) after (run in execution phase as FORST statement - before doLast/<<)"
}
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它会回来
C:\>gradle publish
(1) before (run in configuration phase)
:aoeu
(2) during (run in execution phase as last statement)
:publish
(3) after (run in execution phase as FORST statement - before doLast/<<)
(4) after (run in execution phase as last statement)
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[UPDATE]
这里http://gradle.1045684.n5.nabble.com/task-run-order-lt-lt-syntax-doLast-doFirst-etc-td3337481.html是一个很好的例子,它显示了执行顺序.
[更新]
如果你想运行的任务aoeu在publish执行阶段,你可以调用aoeu.execute的publish.doFirst.但据我所知,不应该这样做.
task publish {
}
task aoeu << {
println "(2) during (run in execution phase as last statement)"
}
tasks.publish.doLast {
println "(3) after (run in execution phase as last statement)"
}
tasks.publish.doFirst {
println "(1) after (run in execution phase as FORST statement - before doLast/<<)"
aoeu.execute()
}
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将返回
C:\>gradle publish
:publish
(1) after (run in execution phase as FORST statement - before doLast/<<)
(2) during (run in execution phase as last statement)
(3) after (run in execution phase as last statement)
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正如我所见,你想aoeu在publish任务中运行.我认为最好的方法是将publish任务分成两个单独的任务并使用depends,mustRunAfter来控制执行顺序.看看这个例子:
task publishInit << {
println '(1)'
}
task aoeu << {
println '(2)'
}
task publish << {
println '(3)'
}
publish.dependsOn publishInit
publish.dependsOn aoeu
aoeu.mustRunAfter publishInit
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它会回来
C:\>gradle publish
:publishInit
(1)
:aoeu
(2)
:publish
(3)
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task snth << {
println "************************* before"
}
task aoeu << {
println "**************************** during aoeu"
}
publish.dependsOn(aoeu)
task ueoa << {
println "**************************** during ueoa"
}
publish.dependsOn(ueoa)
publish.doLast {
println "************************* after"
}
publish.dependsOn.each { dependency ->
if (dependency instanceof Task) {
dependency.dependsOn(snth)
}
}
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将输出:
:snth
************************* before
:aoeu
**************************** during aoeu
:ueoa
**************************** during ueoa
:publish
************************* after
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如果您希望递归添加依赖项:
def recursivelyAddDependsOn(Task parent, Task dependsOn) {
if (!parent.equals(dependsOn)) {
parent.dependsOn(dependsOn)
def tasks = parent.dependsOn.findAll { dependency ->
dependency instanceof Task
}
tasks.each { task ->
recursivelyAddDependsOn(task, dependsOn)
}
}
}
recursivelyAddDependsOn(publish, snth)
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更实用的解决方案是:
def recursivelyApplyToTaskDependencies(Task parent, Closure closure) {
closure(parent)
parent.dependsOn.findAll { dependency ->
dependency instanceof Task
}.each { task ->
recursivelyApplyToTaskDependencies(task, closure)
}
}
def recursivelyAddTaskDependency(Task parent, Task dependency) {
def addTaskDependency = { p ->
if (!p.name.equals(dependency.name)) {
p.dependsOn(dependency)
}
}
recursivelyApplyToTaskDependencies(parent, addTaskDependency)
}
recursivelyAddTaskDependency(publish, snth)
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