use*_*421 0 java concurrency exception
我正在编写一个解决Mastermind游戏的程序.该程序的要点是列出所有可能的解决方案,并在每次猜测不正确之后,从列表中删除任何不至少提供该解决方案的内容.此方法用于比较两个字符串(guess和strFromArray)以查看它们是否获得相同的值.但是,我收到了一个错误,我无法弄清楚原因.任何帮助,将不胜感激.
Exception in thread "main" java.util.ConcurrentModificationException
at java.util.ArrayList$Itr.checkForComodification(Unknown Source)
at java.util.ArrayList$Itr.next(Unknown Source)
at Game.shortenTheList(Game.java:88)
at Game.guess(Game.java:76)
at Game.play(Game.java:40)
at Game.main(Game.java:23)
/*
* Compares the two strings. If they would get the same output, return false. If they would get a different output, return true.
*/
public boolean compare(String guess, String strFromArray, int black, int white)
{
int white2 = 0;
int black2 = 0;
char[] arr1 = guess.toCharArray();
char[] arr2 = strFromArray.toCharArray();
for(int i=0; i<guess.length(); i++)
{
if(arr1[i] == arr2[i])
{
black2 ++;
arr1[i] = '$';
arr2[i] = '%';
}
}
for(int i=0; i<guess.length(); i++)
{
for(int j=0; j<strFromArray.length(); j++)
{
if(arr1[i] == arr2[j])
{
white2++;
arr1[i] = '!';
arr2[j] = '@';
}
}
}
if(black == black2 && white == white2)
return false;
else
return true;
}
/*
* Shortens the list of possible solutions by eliminating everything that wouldn't get at least the given output.
*/
public void shortenTheList(String guess, int black1, int white1)
{
for (String str : possibleSolutions)
{
if(compare(guess, str, black1, white1))
{
possibleSolutions.remove(str);
}
}
}
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一旦你打开一个Iterator
(你做隐式使用时for(String str: possibleSolutions)
,向底层集合的任何修改(possibleSolutions
)除了调用remove
上Iterator
会造成ConcurrentModificationException
;这非常清楚地记录在集合类.
如果您需要从集合中删除项目,请使用以下内容Iterator
:
Iterator<String> it = possibleSolutions.iterator();
while(it.hasNext()) {
if(compare(guess, it.next(), black1, white1))
it.remove();
}
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正如@allprog指出的那样,当你有一个明确的"过滤"问题时,功能方法会更好.直到Java 8是一个选项,使用Guava Iterables#filter
或者Iterables#removeIf
可能是一个不错的选择; 你只需要包装你的compare
方法并传递它.