Hap*_*yPy 5 python dataframe pandas
鉴于这两个数据框:
>>> df1 = pd.DataFrame({'c1':['a','a','b','b'], 'c2':['x','y','x','y'], 'val':0})
>>> df1
c1 c2 val
0 a x 0
1 a y 0
2 b x 0
3 b y 0
>>> df2 = pd.DataFrame({'c1':['a','a','b'], 'c2':['x','y','y'], 'val':[12,31,14]})
>>> df2
c1 c2 val
0 a x 12
1 a y 31
2 b y 14
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是否有一个函数接受valfrom 的元素df2并将它们放在相应的索引中df1,从而导致:
>>> df1_updated
c1 c2 val
0 a x 12
1 a y 31
2 b x 0
3 b y 14
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是的,看看combine_first或更新.例如:
>>> df1['val'] = df2['val'].combine_first(df1['val'])
>>> df1
Out[26]:
c1 c2 val
0 a x 12
1 a y 31
2 b x 14
3 b y 0
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编辑:根据c1和c2组合忽略当前索引:
>>> df1['val'] = df2.set_index(['c1','c2'])['val'].combine_first(df1.set_index(['c1','c2'])['val']).values
>> df1
Out[25]:
c1 c2 val
0 a x 12
1 a y 31
2 b x 0
3 b y 14
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