在UITextView中禁用返回键

Question

我正在尝试禁用在键入时找到的返回键UITextView.我希望文本没有像在a中找到的页面缩进UITextField.这是我到目前为止的代码:

- (BOOL)textView:(UITextView *)aTextView shouldChangeTextInRange:(NSRange)aRange replacementText:(NSString*)aText
{
if ([aTextView.text isEqualToString:@"\r\n"]) {
    return NO;
}

有任何想法吗？

Answer 1

尝试使用这样..

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:(NSString *)text {

    if([text isEqualToString:@"\n"])
    {
        [textView resignFirstResponder];
        return NO;
    }

    return YES;
}

Answer 2

没有魔术硬编码字符串的另一种解决方案是:

- (BOOL)textView:(UITextView *)textView shouldChangeTextInRange:(NSRange)range replacementText:    (NSString *)text {
    if( [text rangeOfCharacterFromSet:[NSCharacterSet newlineCharacterSet]].location == NSNotFound ) {
        return YES;
    }     

    return NO;
}

Answer 3

在Swift 3+中添加:

guard text.rangeOfCharacter(from: CharacterSet.newlines) == nil else {
    return false
}

到顶部 func textView(_ textView: UITextView, shouldChangeTextIn range: NSRange, replacementText text: String) -> Bool