我可以使用带有视图的视图寻呼机(不带片段)

Question

我ViewPager用于刷卡之间Fragments,但我可以使用ViewPager在Views简单的XML布局之间滑动吗？

这是AdapterViewPager的页面,用于在片段之间滑动:

import java.util.List;

import com.app.name.fragments.TipsFragment;

import android.support.v4.app.Fragment;
import android.support.v4.app.FragmentManager;
import android.support.v4.app.FragmentPagerAdapter;
import android.support.v4.app.FragmentTransaction;
import android.view.ViewGroup;

public class PageAdapter extends FragmentPagerAdapter {

    /**
     *
     */
    List<Fragment> fragments;
    public PageAdapter(FragmentManager fm,List<Fragment> frags) {
        super(fm);
        fragments = frags;

    }

    @Override
    public Fragment getItem(int arg0) {
        // TODO Auto-generated method stub
        return TipsFragment.newInstance(0, 0);
    }

    @Override
    public int getCount() {
        // TODO Auto-generated method stub
        return 4;
    }

    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
        FragmentManager manager = ((Fragment) object).getFragmentManager();
        FragmentTransaction trans = manager.beginTransaction();
        trans.remove((Fragment) object);
        trans.commit();

        super.destroyItem(container, position, object);
    }

}

这是我的提示片段:

public class TipsFragment extends Fragment
{
    public static TipsFragment newInstance(int image,int content)
    {
        TipsFragment fragment = new TipsFragment();
        return fragment;
    }

    @Override
    public View onCreateView(LayoutInflater inflater, ViewGroup container,
                             Bundle savedInstanceState) {
        View view = inflater.inflate(R.layout.tip_layout, null);
        return view;
    }
}

如何修改我的代码以使用Views而不是Fragment？

Answer 1

您需要覆盖这两个方法,而不是getItem():

@Override
public Object instantiateItem(ViewGroup collection, int position) {
    View v = layoutInflater.inflate(...);
    ...
    collection.addView(v,0);
    return v;
}

@Override
public void destroyItem(ViewGroup collection, int position, Object view) {
    collection.removeView((View) view);
}

Answer 2

使用此示例

您可以使用嵌套子视图的单个XML布局.

 <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:orientation="vertical">

        <android.support.v4.view.ViewPager
            android:id="@+id/pager"
            android:layout_width="match_parent"
            android:layout_height="match_parent">

            <LinearLayout
                android:id="@+id/page_one"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:orientation="vertical" >
                        <TextView
                        android:text="PAGE ONE IN"
                        android:layout_width="match_parent"
                        android:layout_height="match_parent"
                        android:textColor="#fff"
                        android:textSize="24dp"/>
            </LinearLayout>

            <LinearLayout
                android:id="@+id/page_two"
                android:layout_width="match_parent"
                android:layout_height="match_parent"
                android:orientation="vertical" >
                        <TextView
                        android:text="PAGE TWO IN"
                        android:layout_width="match_parent"
                        android:layout_height="match_parent"
                        android:textColor="#fff"
                        android:textSize="24dp"/>
            </LinearLayout>

    </android.support.v4.view.ViewPager>
</LinearLayout>

但是......你还需要用适配器来处理这个问题.在这里,我们返回查找的视图ID,而不会膨胀任何其他布局.

class WizardPagerAdapter extends PagerAdapter {

    public Object instantiateItem(ViewGroup collection, int position) {

        int resId = 0;
        switch (position) {
        case 0:
            resId = R.id.page_one;
            break;
        case 1:
            resId = R.id.page_two;
            break;
        }
        return findViewById(resId);
    }

    @Override
    public int getCount() {
        return 2;
    }

    @Override
    public boolean isViewFromObject(View arg0, Object arg1) {
        return arg0 == arg1;
    }

    @Override public void destroyItem(ViewGroup container, int position, Object object) {
        // No super
    }
}

//设置ViewPager适配器

WizardPagerAdapter adapter = new WizardPagerAdapter();
ViewPager pager = (ViewPager) findViewById(R.id.pager);
pager.setAdapter(adapter);

Answer 3

根据之前的答案,我做了以下课程,以适当和最清晰的方式实现这一目标(我希望):

public class MyViewPagerAdapter extends PagerAdapter {

    ArrayList<ViewGroup> views;
    LayoutInflater inflater;

    public MyViewPagerAdapter(ActionBarActivity ctx){
        inflater = LayoutInflater.from(ctx);
        //instantiate your views list
        views = new ArrayList<ViewGroup>(5);
    }

    /**
     * To be called by onStop
     * Clean the memory
     */
    public void release(){
     views.clear();
        views = null;
    }

    /**
     * Return the number of views available.
     */
    @Override
    public int getCount() {
        return 5;
    }

    /**
     * Create the page for the given position. The adapter is responsible
     * for adding the view to the container given here, although it only
     * must ensure this is done by the time it returns from
     * {@link #finishUpdate(ViewGroup)}.
     *
     * @param container The containing View in which the page will be shown.
     * @param position The page position to be instantiated.
     * @return Returns an Object representing the new page. This does not
     *         need to be a View, but can be some other container of
     *         the page.  ,container
     */
    public Object instantiateItem(ViewGroup container, int position) {
        ViewGroup currentView;
        Log.e("MyViewPagerAdapter", "instantiateItem for " + position);
        if(views.size()>position&&views.get(position) != null){
            Log.e("MyViewPagerAdapter",
                  "instantiateItem views.get(position) " +
                  views.get(position));
            currentView = views.get(position);
        }
        else{
            Log.e("MyViewPagerAdapter", "instantiateItem need to create the View");
            int rootLayout = R.layout.view_screen;
            currentView = (ViewGroup) inflater.inflate(rootLayout, container, false);

            ((TextView)currentView.findViewById(R.id.txvTitle)).setText("My Views " + position);
            ((TextView)currentView.findViewById(R.id.btnButton)).setText("Button");
            ((ImageView)currentView.findViewById(R.id.imvPicture)).setBackgroundColor(0xFF00FF00);
        }
        container.addView(currentView);
        return currentView;
    }

    /**
     * Remove a page for the given position. The adapter is responsible
     * for removing the view from its container, although it only must ensure
     * this is done by the time it returns from {@link #finishUpdate(ViewGroup)}.
     *
     * @param container The containing View from which the page will be removed.
     * @param position The page position to be removed.
     * @param object The same object that was returned by
     * {@link #instantiateItem(View, int)}.
     */
    @Override
    public void destroyItem(ViewGroup container, int position, Object object) {
        container.removeView((View)object);

    }

    /**
     * Determines whether a page View is associated with a specific key object
     * as returned by {@link #instantiateItem(ViewGroup, int)}. This method is
     * required for a PagerAdapter to function properly.
     *
     * @param view   Page View to check for association with <code>object</code>
     * @param object Object to check for association with <code>view</code>
     * @return true if <code>view</code> is associated with the key object <code>object</code>
     */
    @Override
    public boolean isViewFromObject(View view, Object object) {
        return view==((View)object);
    }
}

你必须在你的活动中设置它:

public class ActivityWithViewsPaged extends ActionBarActivity {

    /**
     * The page Adapter: Manage the list of views (in fact here, its fragments)
     * And send them to the ViewPager
     */
    private MyViewPagerAdapter pagerAdapter;

    /**
     * The ViewPager is a ViewGroup that manage the swipe from left
     * to right to left.
     * Like a listView with a gesture listener...
     */
    private ViewPager viewPager;

    @Override
    protected void onCreate(Bundle savedInstanceState) {

        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_with_views);

        // Find the viewPager
        viewPager = (ViewPager) super.findViewById(R.id.viewpager);

        // Instantiate the PageAdapter
        pagerAdapter = new MyViewPagerAdapter(this);

        // Affectation de l'adapter au ViewPager
        viewPager.setAdapter(pagerAdapter);
        viewPager.setClipToPadding(false);
        viewPager.setPageMargin(12);

        // Add animation when the page are swiped
        // this instanciation only works with honeyComb and more
        // if you want it all version use AnimatorProxy of the nineoldAndroid lib
        //@see:http://stackoverflow.com/questions/15767729/backwards-compatible-pagetransformer
        if(Build.VERSION.SDK_INT >= Build.VERSION_CODES.HONEYCOMB){
            viewPager.setPageTransformer(true, new PageTransformer());
        }
    }

    @Override
    protected void onStop() {
        super.onStop();
        pagerAdapter.release();
    }

XML文件显而易见的是view_screen.xml:

<xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
        android:id="@+id/screen"
        android:layout_width="match_parent"
        android:layout_height="match_parent">

 <TextView
        android:id="@+id/txvTitle"
        android:layout_width="wrap_content"
        android:layout_gravity="center"
        android:layout_height="wrap_content"
        android:layout_marginBottom="5dp"
        android:layout_marginTop="5dp"
        android:shadowColor="#FF00FF"
        android:shadowDx="10"
        android:shadowDy="10"
        android:shadowRadius="5"
        android:textSize="32dp"
        android:textStyle="italic"
        android:background="#FFFFF000"/>
    <LinearLayout
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:background="#FFFF00F0">
        <TextView
            android:id="@+id/txvLeft"
            android:layout_width="wrap_content"
            android:layout_gravity="left"
            android:layout_height="wrap_content"
            android:layout_marginBottom="5dp"
            android:layout_marginTop="5dp"/>
        <TextView
            android:layout_width="wrap_content"
            android:layout_height="wrap_content"
            android:layout_weight="1"/>
        <TextView
            android:id="@+id/txvRight"
            android:layout_width="wrap_content"
            android:layout_gravity="right"
            android:layout_height="wrap_content"
            android:layout_marginBottom="5dp"
            android:layout_marginTop="5dp"/>
    </LinearLayout>
    <Button
        android:id="@+id/btnButton"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_gravity="center"/>
    <ImageView
        android:id="@+id/imvPicture"
        android:layout_width="match_parent"
        android:layout_height="match_parent"
        android:layout_gravity="center"/>
</LinearLayout>

ActivtyMain具有以下布局:

<?xml version="1.0" encoding="utf-8"?>

<android.support.v4.view.ViewPager
    xmlns:android="http://schemas.android.com/apk/res/android"
    android:layout_width="fill_parent"
    android:layout_height="fill_parent"
    android:paddingLeft="24dp"
    android:paddingRight="24dp"
    android:id="@+id/viewpager"
    android:background="#FF00F0F0">
</android.support.v4.view.ViewPager>

非常感谢Brian和Nicholas的回答,我希望我添加一些最清晰的信息,并强调这个功能的一些好的做法.

Answer 4

我们ViewPager有时构建了一个非常简单的子类.

/**
 * View pager used for a finite, low number of pages, where there is no need for
 * optimization.
 */
public class StaticViewPager extends ViewPager {

    /**
     * Initialize the view.
     *
     * @param context
     *            The application context.
     */
    public StaticViewPager(final Context context) {
        super(context);
    }

    /**
     * Initialize the view.
     *
     * @param context
     *            The application context.
     * @param attrs
     *            The requested attributes.
     */
    public StaticViewPager(final Context context, final AttributeSet attrs) {
        super(context, attrs);
    }

    @Override
    protected void onAttachedToWindow() {
        super.onAttachedToWindow();

        // Make sure all are loaded at once
        final int childrenCount = getChildCount();
        setOffscreenPageLimit(childrenCount - 1);

        // Attach the adapter
        setAdapter(new PagerAdapter() {

            @Override
            public Object instantiateItem(final ViewGroup container, final int position) {
                return container.getChildAt(position);
            }

            @Override
            public boolean isViewFromObject(final View arg0, final Object arg1) {
                return arg0 == arg1;

            }

            @Override
            public int getCount() {
                return childrenCount;
            }

            @Override
            public void destroyItem(final View container, final int position, final Object object) {}
        });
    }

}

此类不需要适配器,因为它将从布局加载视图.为了使用它你的项目,只需使用它而不是android.support.v4.view.ViewPager.

所有花哨的东西仍然可以工作,但你不需要为适配器烦恼.

Answer 5

我想在这里添加我的解决方案。既然你不需要使用片段，你仍然可以创建一个PagerAdapter其高度views，而不是fragments到ViewPager。

扩展PagerAdapter而不是FragmentPagerAdapter

public class CustomPagerAdapter extends PagerAdapter {

  private Context context;

  public CustomPagerAdapter(Context context) {
    super();
    this.context = context;
  }


  @Override
  public Object instantiateItem(ViewGroup collection, int position) {
    LayoutInflater inflater = LayoutInflater.from(context);
    View view = null;
    switch (position){
      case 0:
        view = MemoryView.getView(context, collection);
        break;
      case 1:
        view = NetworkView.getView(context, collection);
        break;
      case 2:
        view = CpuView.getView(context, collection);
        break;
    }

    collection.addView(view);
    return view;
  }

  @Override
  public int getCount() {
    return 3;
  }

  @Override
  public boolean isViewFromObject(View view, Object object) {
    return view==object;
  }

  @Override
  public void destroyItem(ViewGroup collection, int position, Object view) {
    collection.removeView((View) view);
  }
}

现在您需要定义三个类，它们将返回views要在viewpager. 类似于CpuView您将拥有MemoryView和NetworkView类。他们每个人都会膨胀他们各自的布局。

public class CpuView {

public static View getView(Context context, ViewGroup collection) {

    LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context
        .LAYOUT_INFLATER_SERVICE);
    return inflater.inflate(R.layout.debugger_cpu_layout, collection, false);
  }
}

最后一个布局将在每个视图中膨胀

    <?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
              android:orientation="vertical"
              android:layout_width="match_parent"
              android:layout_height="match_parent">

    <TextView
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:textColor="#000000"
        android:text="CPU"/>
</LinearLayout>

PS：我写这个答案的原因是因为这里提供的所有解决方案似乎都运行良好，但它们在 PagerAdapter 类本身中夸大了布局。对于大型项目，如果大量与布局相关的代码被夸大了，那么维护就会变得困难。现在在这个例子中，所有的视图都有单独的类和单独的布局。因此，该项目可以轻松维护。