Ske*_*een 7 c++ boost-spirit boost-spirit-qi
在我的boost::spirit语法中,我有以下片段;
implicit_method_declaration = (-(qi::token(ABSTRACT)) >> ...)
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该类型-(qi::token(ABSTRACT)是boost::optional<boost::iterator_range<std::string::iterator>>不过我只使用此结构来检查,如果抽象关键字,其实是存在,那就是,我宁愿-(qi::token(ABSTRACT)有型bool与价值boost::optional<...> operator bool() const.
我将如何实现这一目标?
我想你正在寻找qi::matches[]:
implicit_method_declaration =
qi::matches[qi::token(ABSTRACT)] >> ...;
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另一种方法是使用qi::attr()替代品:
implicit_method_declaration =
(
qi::token(ABSTRACT) >> qi::attr(true)
| qi::attr(false)
) >> ...;
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再次快速演示:http://coliru.stacked-crooked.com/a/ed8bbad53e8c1943
#include <boost/spirit/include/qi.hpp>
namespace qi = boost::spirit::qi;
template <typename It, typename Skipper = qi::space_type>
struct parser : qi::grammar<It, bool(), Skipper>
{
parser() : parser::base_type(implicit_method_declaration)
{
using namespace qi;
implicit_method_declaration = matches["abstract"];
BOOST_SPIRIT_DEBUG_NODES((implicit_method_declaration));
}
private:
qi::rule<It, bool(), Skipper> implicit_method_declaration;
};
bool doParse(const std::string& input)
{
typedef std::string::const_iterator It;
auto f(begin(input)), l(end(input));
parser<It, qi::space_type> p;
bool data;
try
{
bool ok = qi::phrase_parse(f,l,p,qi::space,data);
if (ok)
{
std::cout << "parse success\n";
std::cout << "data: " << data << "\n";
}
else std::cerr << "parse failed: '" << std::string(f,l) << "'\n";
if (f!=l) std::cerr << "trailing unparsed: '" << std::string(f,l) << "'\n";
return ok;
} catch(const qi::expectation_failure<It>& e)
{
std::string frag(e.first, e.last);
std::cerr << e.what() << "'" << frag << "'\n";
}
return false;
}
int main()
{
doParse("abstract");
doParse("static final");
}
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产量
parse success
data: 1
parse success
data: 0
trailing unparsed: 'static final'
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