如何在将上传文件保存到目录之前重命名？

Question

下面是我用来将文件上传到目录的代码.它工作正常.我的主要问题是:

move_uploaded_file()是将上传的文件保存到目录中的一个,我也猜测move_uploaded_file()是为其设置名称的那个.

如何将文件名更改为随机数？

我试过这样做:

$allowedExts = array("gif", "jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end($temp);
if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/jpg") || ($_FILES["file"]["type"] == "image/pjpeg") || ($_FILES["file"]["type"] == "image/x-png") || ($_FILES["file"]["type"] == "image/png")) && ($_FILES["file"]["size"] < 100000) && in_array($extension, $allowedExts)) {
    if ($_FILES["file"]["error"] > 0) {
        echo "Return Code: " . $_FILES["file"]["error"] . "<br>";
    } else {

        $fileName = $temp[0] . "." . $temp[1];
        $temp[0] = rand(0, 3000); //Set to random number
        $fileName;

        if (file_exists("../img/imageDirectory/" . $_FILES["file"]["name"])) {
            echo $_FILES["file"]["name"] . " already exists. ";
        } else {
            move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $_FILES["file"]["name"]);
            echo "Stored in: " . "../img/imageDirectory/" . $_FILES["file"]["name"];
        }
    }
} else {
    echo "Invalid file";
}

我尝试更改变量,例如$ _FILES ["file"] ["name"]并将其替换为$ fileName; 变量,以便可以存储新名称.

Answer 1

您只需通过更改第二个参数中的文件名来更改文件名move_uploaded_file.

代替

move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $_FILES["file"]["name"]);

使用

$temp = explode(".", $_FILES["file"]["name"]);
$newfilename = round(microtime(true)) . '.' . end($temp);
move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $newfilename);

更改为反映您的问题,将根据当前时间生成一个随机数,并附加原始上传文件的扩展名.

Answer 2

你可以试试这个，

$newfilename= date('dmYHis').str_replace(" ", "", basename($_FILES["file"]["name"]));

move_uploaded_file($_FILES["file"]["tmp_name"], "../img/imageDirectory/" . $newfilename);

Answer 3

/* create new name file */
$filename   = uniqid() . "-" . time(); // 5dab1961e93a7-1571494241
$extension  = pathinfo( $_FILES["file"]["name"], PATHINFO_EXTENSION ); // jpg
$basename   = $filename . "." . $extension; // 5dab1961e93a7_1571494241.jpg

$source       = $_FILES["file"]["tmp_name"];
$destination  = "../img/imageDirectory/{$basename}";

/* move the file */
move_uploaded_file( $source, $destination );

echo "Stored in: {$destination}";

Answer 4

你猜对了。阅读手册页move_uploaded_file。将第二个参数设置为您想要保存文件的任何位置。

如果它不起作用，则您的$fileName. 请发布您最近的代码。