android.os.networkonmainthreadexception在新的Thread中

Question

我知道你不能在主线程中做网络操作,因为Android 3.0.所以,我在一个新的内部打了个电话Thread:

button.setOnClickListener(new OnClickListener() {

    @Override
    public void onClick(View v) {
        user=login.getText().toString();
        password=pass.getText().toString();
        params.add(new BasicNameValuePair("user", user));
        params.add(new BasicNameValuePair("pass", password));
        Thread thread=new Thread(){
            public void run(){
                try {
                    // Throws exception here
                    response=CustomHttpClient.executeHttpPost(urlogin, params); 
                    response=response.replaceAll("\\s+","");

                } catch (Exception e) {
                    e.printStackTrace();
                }
                if(response.equals("ok")){

                    Intent home=new Intent(c, HomeActivity.class);
                    home.putExtra("username", user);
                    startActivity(home);
                    Toast toast=Toast.makeText(
                        c, getString(R.string.welcome), Toast.LENGTH_LONG);
                    toast.show();
                }else{
                    if(response.equals("fallo")){
                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                Toast toast=Toast.makeText(
                                    c, R.string.nologin, Toast.LENGTH_LONG);
                                toast.show();
                                login.setText("");
                                pass.setText("");
                            }
                        });
                    }else if(response.equals("nologin")){
                        runOnUiThread(new Runnable() {

                            @Override
                            public void run() {
                                Toast toast=Toast.makeText(
                                    c, R.string.nouser, Toast.LENGTH_LONG);
                                toast.show();
                                login.setText("");
                                pass.setText("");

                            }
                        });
                    }
                }
            }
        };
        thread.run();
    }
});

但是,尽管我没有主线程(或者至少我认为......),我收到了这个例外.

Answer 1

using run()没有启动一个单独的线程,它实际上在启动它的同一个线程上启动了一个runnable.

你需要用来start()开始一个新的线程.