AngularJS:我应该如何更新监视器侦听器内已解析的promise的属性?

Jim*_* G. 7 promise angularjs

考虑一下这个Plunkr.

在我的监听器内部,我想根据已解决的承诺更新属性.

  • 修改属性上的值是否正确$$v
  • 如果没有,那我该怎么办?

这是HTML:

<!DOCTYPE html>
<html id="ng-app" ng-app="myAngularApp">

  <head>
    <script data-require="angular.js@*" data-semver="1.2.0-rc2" src="http://code.angularjs.org/1.2.0-rc.2/angular.js"></script>
    <script src="script.js"></script>
  </head>

  <body ng-controller="MyController">
    <input ng-model="myDto.Weight" />{{myDto.Status}}
  </body>

</html>
Run Code Online (Sandbox Code Playgroud)

这是JavaScript:

var myDto = {Weight: 200, Status: 'Acceptable'};

var myAngularApp = angular.module('myAngularApp', []);

myAngularApp.factory('myService', function($q){
  return {
    getMyDto: function(){
      var deferred = $q.defer();
      deferred.resolve(myDto);
      return deferred.promise;
    }
  };
});

myAngularApp.controller('MyController', function MyController($scope, myService){
  $scope.myDto = myService.getMyDto();
  $scope.$watch('myDto.Weight', function(newVal, oldVal){
    if (newVal < 150) {
      $scope.myDto.$$v.Status = 'Too Light!'; // Is this the recommended way of doing it?
    }
    else if (500 < newVal) {
      $scope.myDto.$$v.Status = 'Too Heavy!';
    }
    else if (Number(newVal)) {
      $scope.myDto.$$v.Status = 'Acceptable';
    }
    else {
      $scope.myDto.$$v.Status = 'Not a number!';
    }
  });
});
Run Code Online (Sandbox Code Playgroud)

Buu*_*yen 8

我不会$$v直接修改,这是一个实现细节.相反,then用来获得承诺的结果,然后随意使用它.这需要对代码进行最少的更改.

演示链接

myAngularApp.controller('MyController', function MyController($scope, myService){
  ($scope.myDto = myService.getMyDto()).then(function(myDto) {
    $scope.$watch('myDto.Weight', function(newVal, oldVal){
      if (newVal < 150) {
        myDto.Status = 'Too Light!'; // Is this the recommended way of doing it?
      }
      else if (500 < newVal) {
        myDto.Status = 'Too Heavy!';
      }
      else if (Number(newVal)) {
        myDto.Status = 'Acceptable';
      }
      else {
        myDto.Status = 'Not a number!';
      }
    });
  });
});
Run Code Online (Sandbox Code Playgroud)