Phonegap(3.0.0)首次尝试时相机未成功

Question

Phonegap(3.0.0)首次尝试时相机未成功

Ian*_*ell 8 javascript camera android cordova

出于测试目的,我复制了在phonegap相机API上找到的完整示例,并在onPhotoDataSuccess触发该功能时发出警报以进行测试.在拍摄的第一张照片上,警报将不会显示.但是,在第一次尝试后,警报将在照片保存后显示.

有什么建议？如果事情不清楚,我会很高兴更具体.

我在Android Galaxy S3上测试了下面的代码

    <!DOCTYPE html>
<html>
  <head>
    <title>Capture Photo</title>

    <script type="text/javascript" charset="utf-8" src="cordova.js"></script>
    <script type="text/javascript" charset="utf-8">

    var pictureSource;   // picture source
    var destinationType; // sets the format of returned value

    // Wait for device API libraries to load
    //
    document.addEventListener("deviceready",onDeviceReady,false);

    // device APIs are available
    //
    function onDeviceReady() {
        pictureSource=navigator.camera.PictureSourceType;
        destinationType=navigator.camera.DestinationType;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoDataSuccess(imageData) {
      // Uncomment to view the base64-encoded image data
      // console.log(imageData);

      // Get image handle
      //
      var smallImage = document.getElementById('smallImage');

      // Unhide image elements
      //
      smallImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      smallImage.src = "data:image/jpeg;base64," + imageData;
    }

    // Called when a photo is successfully retrieved
    //
    function onPhotoURISuccess(imageURI) {
      // Uncomment to view the image file URI
      // console.log(imageURI);

      // Get image handle
      //
      var largeImage = document.getElementById('largeImage');

      // Unhide image elements
      //
      largeImage.style.display = 'block';

      // Show the captured photo
      // The inline CSS rules are used to resize the image
      //
      largeImage.src = imageURI;
    }

    // A button will call this function
    //
    function capturePhoto() {
      // Take picture using device camera and retrieve image as base64-encoded string
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50,
        destinationType: destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function capturePhotoEdit() {
      // Take picture using device camera, allow edit, and retrieve image as base64-encoded string
      navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 20, allowEdit: true,
        destinationType: destinationType.DATA_URL });
    }

    // A button will call this function
    //
    function getPhoto(source) {
      // Retrieve image file location from specified source
      navigator.camera.getPicture(onPhotoURISuccess, onFail, { quality: 50,
        destinationType: destinationType.FILE_URI,
        sourceType: source });
    }

    // Called if something bad happens.
    //
    function onFail(message) {
      alert('Failed because: ' + message);
    }

    </script>
  </head>
  <body>
    <button onclick="capturePhoto();">Capture Photo</button> <br>
    <button onclick="capturePhotoEdit();">Capture Editable Photo</button> <br>
    <button onclick="getPhoto(pictureSource.PHOTOLIBRARY);">From Photo Library</button><br>
    <button onclick="getPhoto(pictureSource.SAVEDPHOTOALBUM);">From Photo Album</button><br>
    <img style="display:none;width:60px;height:60px;" id="smallImage" src="" />
    <img style="display:none;" id="largeImage" src="" />
  </body>
</html>

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----------更新1 ------------------

我在另一段代码上测试了它:

    (function () {
        $scroller = $('.scroller'),

        // Take a picture using the camera or select one from the library
        takePicture = function (e) {
            var options = {
                quality: 45,
                targetWidth: 1000,
                targetHeight: 1000,
                destinationType: Camera.DestinationType.FILE_URI,
                encodingType: Camera.EncodingType.JPEG,
                sourceType: Camera.PictureSourceType.CAMERA
            };

            navigator.camera.getPicture(
                function (imageURI) {
                    console.log(imageURI);
                    alert('test');
                    $scroller.append('<img src="' + imageURI + '"/>');
                },
                function (message) {
                    // We typically get here because the use canceled the photo operation. Fail silently.
                }, options);

            return false;

        };

    $('.camera-btn').on('click', takePicture);

}());

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这也有同样的效果.它在第一次拍摄时不执行任何操作,但在第二次拍摄后显示照片.我还发现第二张照片后拍摄的照片是我拍摄的第一张照片.似乎getPicture中的第一个参数在第一次捕捉时没有触发.这令人沮丧,因为logcat并没有真正向我展示任何可用的东西.

----------------更新2 ----------------

我刚刚在Phonegap Build上试了一下它就可以了.所以它必须与插件有关...

Answer 1

Chi*_*iya 1

我不知道这是否是正确的解决方案，但它对我来说非常有用。追踪你的日志猫并找到确切的问题会更好。

尝试使用navigator.camera.PictureSourceTypeinstated of pictureSource。所以看起来像

<button onclick="getPhoto(navigator.camera.PictureSourceType.PHOTOLIBRARY);">From Photo Library</button><br>

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并以同样的方式替换 Javascript 代码

navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50, destinationType: navigator.camera.DestinationType.FILE_URI });

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或者

navigator.camera.getPicture(onPhotoDataSuccess, onFail, { quality: 50, destinationType: navigator.camera.DestinationType.DATA_URI });

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更新： 尝试在本地保存你的 corodova.js 并从本地目录调用，所以你的目录应该像

assets/www/js/cordova.js

<script type="text/javascript" charset="utf-8" src="js/cordova.js"></script>

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工作代码

希望对你有帮助！！！

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