Mih*_*ian 59 python numpy pandas
我有一个形状(X,Y)的Pandas数据框对象,如下所示:
[[1, 2, 3],
[4, 5, 6],
[7, 8, 9]]
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形状(X,Z)的numpy稀疏矩阵(CSC)看起来像这样
[[0, 1, 0],
[0, 0, 1],
[1, 0, 0]]
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如何将矩阵中的内容添加到新命名列中的数据框中,以使数据框最终如下:
[[1, 2, 3, [0, 1, 0]],
[4, 5, 6, [0, 0, 1]],
[7, 8, 9, [1, 0, 0]]]
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请注意,数据框现在具有形状(X,Y + 1),矩阵中的行是数据框中的元素.
unu*_*tbu 56
import numpy as np
import pandas as pd
import scipy.sparse as sparse
df = pd.DataFrame(np.arange(1,10).reshape(3,3))
arr = sparse.coo_matrix(([1,1,1], ([0,1,2], [1,2,0])), shape=(3,3))
df['newcol'] = arr.toarray().tolist()
print(df)
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产量
0 1 2 newcol
0 1 2 3 [0, 1, 0]
1 4 5 6 [0, 0, 1]
2 7 8 9 [1, 0, 0]
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Max*_*chi 13
df = pd.DataFrame(np.arange(1,10).reshape(3,3))
df['newcol'] = pd.Series(your_2d_numpy_array)
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考虑使用更高维度的数据结构(Panel),而不是在列中存储数组:
In [11]: p = pd.Panel({'df': df, 'csc': csc})
In [12]: p.df
Out[12]:
0 1 2
0 1 2 3
1 4 5 6
2 7 8 9
In [13]: p.csc
Out[13]:
0 1 2
0 0 1 0
1 0 0 1
2 1 0 0
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看看横截面等等等.
In [14]: p.xs(0)
Out[14]:
csc df
0 0 1
1 1 2
2 0 3
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您可以使用以下命令从数据框中添加和检索 numpy 数组:
import numpy as np
import pandas as pd
df = pd.DataFrame({'b':range(10)}) # target dataframe
a = np.random.normal(size=(10,2)) # numpy array
df['a']=a.tolist() # save array
np.array(df['a'].tolist()) # retrieve array
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这是建立在之前的答案的基础上的,该答案由于稀疏部分而让我感到困惑,并且这对于非稀疏 numpy 数组非常有效。
小智 5
这是另一个例子:
import numpy as np
import pandas as pd
""" This just creates a list of tuples, and each element of the tuple is an array"""
a = [ (np.random.randint(1,10,10), np.array([0,1,2,3,4,5,6,7,8,9])) for i in
range(0,10) ]
""" Panda DataFrame will allocate each of the arrays , contained as a tuple
element , as column"""
df = pd.DataFrame(data =a,columns=['random_num','sequential_num'])
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一般来说,秘密是以 a = [ (array_11, array_12,...,array_1n),...,(array_m1,array_m2,...,array_mn) ] 的形式分配数据,并且 panda DataFrame 将对数据进行排序在 n 列数组中。当然,可以使用数组的数组代替元组,在这种情况下,形式为: a = [ [array_11, array_12,...,array_1n],...,[array_m1,array_m2,...,array_mn ]]
如果从上面的代码中 print(df) ,这就是输出:
random_num sequential_num
0 [7, 9, 2, 2, 5, 3, 5, 3, 1, 4] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
1 [8, 7, 9, 8, 1, 2, 2, 6, 6, 3] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
2 [3, 4, 1, 2, 2, 1, 4, 2, 6, 1] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
3 [3, 1, 1, 1, 6, 2, 8, 6, 7, 9] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
4 [4, 2, 8, 5, 4, 1, 2, 2, 3, 3] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5 [3, 2, 7, 4, 1, 5, 1, 4, 6, 3] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
6 [5, 7, 3, 9, 7, 8, 4, 1, 3, 1] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
7 [7, 4, 7, 6, 2, 6, 3, 2, 5, 6] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
8 [3, 1, 6, 3, 2, 1, 5, 2, 2, 9] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
9 [7, 2, 3, 9, 5, 5, 8, 6, 9, 8] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
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上例的其他变体:
b = [ (i,"text",[14, 5,], np.array([0,1,2,3,4,5,6,7,8,9])) for i in
range(0,10) ]
df = pd.DataFrame(data=b,columns=['Number','Text','2Elemnt_array','10Element_array'])
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df 的输出:
Number Text 2Elemnt_array 10Element_array
0 0 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
1 1 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
2 2 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
3 3 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
4 4 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
5 5 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
6 6 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
7 7 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
8 8 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
9 9 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
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如果要添加数组的其他列,则:
df['3Element_array']=[([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3]),([1,2,3])]
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df 的最终输出将是:
Number Text 2Elemnt_array 10Element_array 3Element_array
0 0 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
1 1 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
2 2 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
3 3 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
4 4 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
5 5 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
6 6 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
7 7 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
8 8 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
9 9 text [14, 5] [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] [1, 2, 3]
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