如何仅在列日期时间中按日期分组

Question

我在SQL Server Express 2005中进行分组时遇到问题

我有一个,DATETIME COLUMN但我想只按日期分组.

这是我的SQL语句:

SELECT (u.FirstName + ' ' + u.LastName) AS [FullName],d.user_id,CONVERT(varchar,d.log_date,101) AS log_date, min(d.login_time) as LOG_IN, max(d.logout_time) as LOG_OUT, sum(d.totaltime) as TOTHrs 
FROM tbldtr d INNER JOIN tblUsers u ON d.user_id = u.User_Id
WHERE d.user_id = 'ADMIN1' and d.log_date BETWEEN '6/1/2013' AND '6/15/2013'
GROUP BY DATEADD(day, DATEDIFF(day, 0, log_date), 0),u.FirstName,u.LastName,d.user_id order by d.log_date asc

但它给了我这个错误:

列'tbldtr.log_date'在选择列表中无效,因为它不包含在聚合函数或GROUP BY子句中.

提前致谢.!

Answer 1

刚convert(varchar,d.log_date,101)进入group by条款:

select
    u.FirstName + ' ' + u.LastName as [FullName],
    d.user_id,
    convert(varchar, d.log_date, 101) as log_date,
    min(d.login_time) as LOG_IN,
    max(d.logout_time) as LOG_OUT,
    sum(d.totaltime) as TOTHrs 
from tbldtr d
    inner join tblUsers u on d.user_id = u.User_Id
where d.user_id = 'ADMIN1' and d.log_date between '20130601' AND '20130615'
group by
     convert(varchar, d.log_date, 101),
     u.FirstName, u.LastName, d.user_id
order by log_date asc

此外,以where明确的格式更改日期更安全-YYYYMMDD