我有以下IF条件,但它总是给我最后的$ genreid 6000
if ($URL == "/apps.html"
or "/apps/all-genres.html"
or "/apps/all-genres/top-paid-apps.html"
or "/apps/all-genres/top-free-apps.html"
) {
$genreid = "36";
}
if ($URL == "/apps/business.html"
or "/apps/business/top-paid-apps.html"
or "/apps/business/top-free-apps.html"
) {
$genreid = "6000";
}
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有人可以帮我纠正这个吗?
你的所有人都搞砸了.OR"foo"将解决为真.
尝试这样的事情:
if (in_array($URL,array('test1','test2','test3') ))
{
$genreid = "36";
}
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