Vin*_*ano 12 jquery jquery-validate
我试图showErrors从函数内调用jQuery验证函数,submitHandler而不必像这样保存验证器对象:
var validator = $( "#myshowErrors" ).validate();
validator.showErrors({
"firstname": "I know that your firstname is Pete, Pete!"
});
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有没有办法从submitHandler方法中获取验证器对象,如下所示:
$( "#myshowErrors" ).validate({
submitHandler : function(form) {
$(form).ajaxSubmit({
success : function(result) {
var validator = // Get validator here somehow?
validator.showErrors(result.fieldErrors);
}
});
}
});
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通过这种方式,我希望我可以submitHandler在整个项目的多个地方使用相同的方法.
Krz*_*iek 19
Validator对象存储在表单元素数据中:
var validator = $.data( form, "validator");
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编辑:
实际上验证器也应该存储在this:
$( "#myshowErrors" ).validate({
submitHandler : function(form) {
var validator = this;
$(form).ajaxSubmit({
success : function(result) {
validator.showErrors(result.fieldErrors);
}
});
}
});
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