有人可以看一下这段代码并找出它有什么问题吗？
#!/bin/sh
while :
do
echo " Select one of the following options:"
echo " d or D) Display today's date and time"
echo " l or L) List the contents of the present working directory"
echo " w or W) See who is logged in"
echo " p or P) Print the present working directory"
echo " a or A) List the contents of a specified directory"
echo " b or B) Create a backup copy of an ordinary file"
echo " q or Q) Quit this program"
echo " Enter your option and hit <Enter>: \c"
read option
case "$option" in
d|D) date
;;
l|L) ls $PWD
;;
w|w) who
;;
p|P) pwd
;;
a|A) echo "Please specify the directory and hit <Enter>: \c"
read directory
if [ "$directory = "q" -o "Q" ]
then
exit 0
fi
while [ ! -d "$directory" ]
do
echo "Usage: "$directory" must be a directory."
echo "Re-enter the directory and hit <Enter>: \c"
read directory
if [ "$directory" = "q" -o "Q" ]
then
exit 0
fi
done
printf ls "$directory"
;;
b|B) echo "Please specify the ordinary file for backup and hit <Enter>: \c"
read file
if [ "$file" = "q" -o "Q" ]
then
exit 0
fi
while [ ! -f "$file" ]
do
echo "Usage: \"$file\" must be an ordinary file."
echo "Re-enter the ordinary file for backup and hit <Enter>: \c"
read file
if [ "$file" = "q" -o "Q" ]
then
exit 0
fi
done
cp "$file" "$file.bkup"
;;
q|Q) exit 0
;;
esac
echo
done
exit 0
有一些我无法弄清楚的语法错误.但是我应该注意,在这个unix系统上,echo -e不起作用(不要问我为什么我不知道,我没有任何权限来改变它,即使我不被允许至)
Bash Shell脚本错误:"./ myDemo./ myDemo:第62行:意外令牌附近的语法错误done' ./myDemo: line 62:"[已编辑]
编辑:我修复了while语句错误,但是现在当我运行脚本时,一些东西仍然无法正常工作.
似乎在b | B)中切换语句
cp $ file $ file.bkup实际上并没有将文件复制到file.bkup？
在a | A)开关语句中
ls"$ directory"不打印用户看到的目录列表？
#!/bin/bash
while $TRUE
do
echo " Select one of the following options:"
echo " d or D) Display today's date and time"
echo " l or L) List the contents of the present working directory"
echo " w or W) See who is logged in"
echo " p or P) Print the present working directory"
echo " a or A) List the contents of a specified directory"
echo " b or B) Create a backup copy of an ordinary file"
echo " q or Q) Quit this program"
echo " Enter your option and hit <Enter>: \c"
read option
case "$option" in
d|D) date
;;
l|L) ls pwd
;;
w|w) who
;;
p|P) pwd
;;
a|A) echo "Please specify the directory and hit <Enter>: \c"
read directory
if [ ! -d "$directory" ]
then
while [ ! -d "$directory" ]
do
echo "Usage: "$directory" must be a directory."
echo "Specify the directory and hit <Enter>: \c"
read directory
if [ "$directory" = "q" -o "Q" ]
then
exit 0
elif [ -d "$directory" ]
then
ls "$directory"
else
continue
fi
done
fi
;;
b|B) echo "Specify the ordinary file for backup and hit <Enter>: \c"
read file
if [ ! -f "$file" ]
then
while [ ! -f "$file" ]
do
echo "Usage: "$file" must be an ordinary file."
echo "Specify the ordinary file for backup and hit <Enter>: \c"
read file
if [ "$file" = "q" -o "Q" ]
then
exit 0
elif [ -f "$file" ]
then
cp $file $file.bkup
fi
done
fi
;;
q|Q) exit 0
;;
esac
echo
done
exit 0
另一件事......是否有一个我可以用来自动解析代码的编辑器？即类似NetBeans的东西？
你错过了do第二个while.('B'案例;将其与上面的'A'案例进行比较.)
我使用gvim,它将语法突出显示shell脚本,但我认为你需要将编辑器作为一个单独的问题.
至于你的问题修改:你的逻辑被打破同时在A和B情况:你需要拉逻辑备份你的,如果/当...嵌套在的if你实际上并没有做任何事情.此外,请务必引用所有文件名,以便空格不会破坏您的脚本.转义嵌套引号.我相信你需要一个-e使用的echo语句\c.
所以做一些更像是:
b|B) echo -e "Specify the ordinary file for backup and hit <Enter>: \c"
read file
while [ ! -f "$file" ]
do
echo "Usage: \"$file\" must be an ordinary file."
echo -e "Specify the ordinary file for backup and hit <Enter>: \c"
read file
if [ "$file" = "q" -o "$file" = "Q" ]
then
exit 0
fi
done
cp "$file" "$file.bkup"
;;
您需要对A案例进行相同类型的更改.
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