Flask:带有可变参数的URL

Question

我有一个我希望以下列方式构建的URL字符串:

http://something.com/mainsite/key1/key2/key3/keyn

如何在我的URL映射中生成类似这样的内容,其中n是变量号？

我如何获得这些钥匙？

谢谢

Answer 1

有两种方法可以做到这一点:

1. 只需使用path路线转换器:

   @app.route("/mainsite/<path:varargs>")
   def api(varargs=None):
       # for mainsite/key1/key2/key3/keyn
       # `varargs` is a string contain the above
       varargs = varargs.split("/")
       # And now it is a list of strings
   

2. 注册您自己的自定义路由转换器(有关完整详细信息,请参阅Werkzeug的文档):

   from werkzeug.routing import BaseConverter, ValidationError
   
   class PathVarArgsConverter(BaseConverter):
       """Convert the remaining path segments to a list"""
   
       def __init__(self, url_map):
           super(PathVarArgsConverter, self).__init__(url_map)
           self.regex = "(?:.*)"
   
       def to_python(self, value):
           return value.split(u"/")
   
       def to_url(self, value):
           return u"/".join(value)
   
   app.url_map.converters['varargs'] = PathVarArgsConverter
   

   你可以这样使用:

   @app.route("/mainsite/<varargs:args>")
   def api(args):
       # args here is the list of path segments