在快速路由中确定socket.io服务器端和客户端对象的范围

Question

在我的app.js中我有

var app = express();
var serv = http.createServer(app);
var io = require('socket.io').listen(serv);
io.sockets.on('connection', function(socket) {
   //some code here
}

var SessionSockets = require('session.socket.io'),
    sessionSockets = new SessionSockets(io, express_store, cookieParser);
sessionSockets.on('connection', function (err, socket, session) {
   //set up some socket handlers here for the specific client  that are 
   //only called when a client does a socket.emit. 
   //These handlers have access to io, sessionSockets, socket, session objects.
}

快速路由如何在处理post/get之后访问特定客户端的套接字引用,该post/get不是由客户端socket.emit触发但是由客户端post/get触发.socket.io server(io/sessionSockets)/client(socket)在路由中对对象进行范围限定的最佳方法是什么,以便我可以轻松获取此客户端的套接字引用？

Answer 1

这三个步骤帮助我解决了问题.这也标识了标签,因为这是我的要求之一.

1. 在连接时,使用连接,socket.id然后使用socket.id返回到客户端

   io.sockets.on('connection', function(socket) {
     socket.join(socket.id);   
     socket.emit('server_socket_id', {socket_id : socket.id});
   }
   

2. 客户端使用接收emit事件

   socket.on('server_socket_id', function(data){
     //assign some global here which can be sent back to the server whenever required.
     server_socket_id = data.socket_id;
   });
   

3. app.js我在这里获取相应的套接字并将其传递给路由.

   app.post('/update', function(req, res){
     var socket_id = req.body.socket_id;
     route.update(req, res, io.sockets.in(socket_id).sockets[socket_id]);
   });