Excel查找速度与VBA二进制搜索?

Exc*_*ist 6 sorting excel vba binary-search excel-vba

Excel VBA的查找与二进制搜索有多好/多快?我的平台是Office 11 | 2003,我将在三张值上搜索A列的字符串.行总数~14万

如果值得我参考哪个库和函数进行排序然后进行二分查找?据报道,二进制搜索字符串/文本存在潜在问题.

......必须注意一件事.使用带有sortedtext的二进制搜索公式需要谨慎. Aladin A.,Excel MVP

Excel查找:

Worksheets(1).Range("A:A").Find("PN-String-K9", LookIn:=xlValues, LookAt:=xlWhole)
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mik*_*may 7

与我的直觉相反,VBA二进制搜索强烈优于Excel查找.至少在下面的场景中,120,000个6个字符串均匀分布在3个工作表上.

Excel查找需要1分58秒,
VBA二进制搜索在我的特定计算机上需要36秒.

知道文本有序的好处显然超过了Excel的天然优势.注意Aladin A关于排序顺序的警告.

Option Explicit

' Call Search to look for a thousand random strings
' in 3 worksheets of a workbook

' requires a workbook with 3 sheets and
' column A populated with values between "00001" to "120000"
' split evenly 40,000 to a worksheet in ascending order.
' They must be text, not numbers.

Private Const NUM_ROWS As Long = 120000
Private Const SHEET_1 As String = "Sheet1"
Private Const SHEET_2 As String = "Sheet2"
Private Const SHEET_3 As String = "Sheet3"

' This uses VBA Binary Search
Public Sub Search()
    Worksheets(SHEET_1).Range("B:B").ClearContents
    Worksheets(SHEET_2).Range("B:B").ClearContents
    Worksheets(SHEET_3).Range("B:B").ClearContents
    DoSearch True       ' change to False to test Excel search
End Sub

' Searches for a thousand values using binary  or excel search depending on
' value of bBinarySearch
Public Sub DoSearch(ByVal bBinarySearch As Boolean)
    Debug.Print Now
    Dim ii As Long

    For ii = 1 To 1000
        Dim rr As Long
        rr = Int((NUM_ROWS) * Rnd + 1)
        If bBinarySearch Then
            Dim strSheetName As String
            Dim nRow As Long
            If BinarySearch(MakeSearchArg(rr), strSheetName, nRow) Then
                Worksheets(strSheetName).Activate
                Cells(nRow, 1).Activate
            End If
        Else
            If Not ExcelSearch(SHEET_1, MakeSearchArg(rr)) Then
                If Not ExcelSearch(SHEET_2, MakeSearchArg(rr)) Then
                    ExcelSearch SHEET_3, MakeSearchArg(rr)
                End If
            End If
        End If
        ActiveCell.Offset(0, 1).Value = "FOUND"
    Next
    Debug.Print Now

End Sub

' look for one cell value using Excel Find
Private Function ExcelSearch(ByVal strWorksheet As String _
  , ByVal strSearchArg As String) As Boolean
    On Error GoTo Err_Exit
    Worksheets(strWorksheet).Activate
    Worksheets(strWorksheet).Range("A:A").Find(What:=strSearchArg, LookIn:=xlValues, LookAt:= 
        xlWhole, SearchOrder:=xlByRows, SearchDirection:=xlNext, MatchCase:=True 
        , SearchFormat:=False).Activate
    ExcelSearch = True
    Exit Function
Err_Exit:
    ExcelSearch = False
End Function

' Look for value using a vba based binary search
' returns true if the search argument is found in the workbook
' strSheetName contains the name of the worksheet on exit and nRow gives the row
Private Function BinarySearch(ByVal strSearchArg As String _
  , ByRef strSheetName As String, ByRef nRow As Long) As Boolean
    Dim nFirst As Long, nLast As Long
    nFirst = 1
    nLast = NUM_ROWS
    Do While True
        Dim nMiddle As Long
        Dim strValue As String
        If nFirst > nLast Then
            Exit Do     ' Failed to find search arg
        End If
        nMiddle = Round((nLast - nFirst) / 2 + nFirst)
        SheetNameAndRowFromIdx nMiddle, strSheetName, nRow
        strValue = Worksheets(strSheetName).Cells(nRow, 1)
        If strSearchArg < strValue Then
            nLast = nMiddle - 1
        ElseIf strSearchArg > strValue Then
            nFirst = nMiddle + 1
        Else
            BinarySearch = True
            Exit Do
        End If
    Loop
End Function

' convert 1 -> "000001", 120000 -> "120000", etc
Private Function MakeSearchArg(ByVal nArg As Long) As String
    MakeSearchArg = Right(CStr(nArg + 1000000), 6)
End Function

' converts some number to a worksheet name and a row number
' This is depenent on the worksheets being named sheet1, sheet2, sheet3

' and containing an equal number of vlaues in each sheet where
' the total number of values is NUM_ROWS
Private Sub SheetNameAndRowFromIdx(ByVal nIdx As Long _
  , ByRef strSheetName As String, ByRef nRow As Long)
    If nIdx <= NUM_ROWS / 3 Then

        strSheetName = SHEET_1
        nRow = nIdx
    ElseIf nIdx > (NUM_ROWS / 3) * 2 Then
        strSheetName = SHEET_3
        nRow = nIdx - (NUM_ROWS / 3) * 2
    Else
        strSheetName = SHEET_2
        nRow = nIdx - (NUM_ROWS / 3)
    End If
End Sub
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  • 将 `nMiddle = Round((nLast - nFirst) / 2 + nFirst)` 替换为 `nMiddle = (nLast + nFirst) \ 2` 几乎可以使变体数组上的二分搜索速度提高一倍。 (2认同)