use*_*205 41 jquery json controller spring-mvc
我需要向Spring MVC controller发送一个JSON字符串.但我没有任何表单绑定,我只需要向Controller类发送一个简单的JSON数据.我正在对Controller方法进行jQuery AJAX调用,如下面的代码.
$.ajax ({
url: "./save",
type: "POST",
data: JSON.stringify(array),
dataType: "json",
contentType: "application/json; charset=utf-8",
success: function(){
alert("success ");
}
});
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但是我如何在Controller方法中检索它?(注意:它只是简单的JSON数据而不是表单提交).
Vin*_*ran 47
添加以下依赖项
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-mapper-asl</artifactId>
<version>1.9.7</version>
</dependency>
<dependency>
<groupId>org.codehaus.jackson</groupId>
<artifactId>jackson-core-asl</artifactId>
<version>1.9.7</version>
</dependency>
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修改请求如下
$.ajax({
url:urlName,
type:"POST",
contentType: "application/json; charset=utf-8",
data: jsonString, //Stringified Json Object
async: false, //Cross-domain requests and dataType: "jsonp" requests do not support synchronous operation
cache: false, //This will force requested pages not to be cached by the browser
processData:false, //To avoid making query String instead of JSON
success: function(resposeJsonObject){
// Success Message Handler
}
});
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控制器端
@RequestMapping(value = urlPattern , method = RequestMethod.POST)
public @ResponseBody Person save(@RequestBody Person jsonString) {
Person person=personService.savedata(jsonString);
return person;
}
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@RequestBody- 将Json对象隐藏到java
@ResponseBody- 将Java对象转换为json
小智 6
HTML
$('#save').click(function(event) {
var jenis = $('#jenis').val();
var model = $('#model').val();
var harga = $('#harga').val();
var json = { "jenis" : jenis, "model" : model, "harga": harga};
$.ajax({
url: 'phone/save',
data: JSON.stringify(json),
type: "POST",
beforeSend: function(xhr) {
xhr.setRequestHeader("Accept", "application/json");
xhr.setRequestHeader("Content-Type", "application/json");
},
success: function(data){
alert(data);
}
});
event.preventDefault();
});
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调节器
@Controller
@RequestMapping(value="/phone")
public class phoneController {
phoneDao pd=new phoneDao();
@RequestMapping(value="/save",method=RequestMethod.POST)
public @ResponseBody
int save(@RequestBody Smartphones phone)
{
return pd.save(phone);
}
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public Integer save(Smartphones i) {
int id = 0;
Session session=HibernateUtil.getSessionFactory().openSession();
Transaction trans=session.beginTransaction();
try {
session.save(i);
id=i.getId();
trans.commit();
}
catch(HibernateException he){}
return id;
}
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