从Windows批处理执行Python脚本时相对路径是否中断？

Question

如果我直接从它所在的目录中执行它,我的Python脚本就可以正常工作.但是如果我退出该目录并尝试从其他地方执行它(不更改任何代码或文件位置),所有相对路径都会中断得到一个FileNotFoundError.

该脚本位于./scripts/bin/my_script.py.有一个名为的目录./scripts/bin/data/.就像我说的那样,只要我从同一个目录执行它就完全可以工作......所以我很困惑.

成功执行(in ./scripts/bin/):python my_script.py

执行失败(in ./scripts/):两者python bin/my_script.py和python ./bin/my_script.py

失败消息:

Traceback (most recent call last):
  File "./bin/my_script.py", line 87, in <module>
    run()
  File "./bin/my_script.py", line 61, in run
    load_data()
  File "C:\Users\XXXX\Desktop\scripts\bin\tables.py", line 12, in load_data
DATA = read_file("data/my_data.txt")
  File "C:\Users\XXXX\Desktop\scripts\bin\fileutil.py", line 5, in read_file
    with open(filename, "r") as file:
FileNotFoundError: [Errno 2] No such file or directory: 'data/my_data.txt'

相关的Python代码:

def read_file(filename):
    with open(filename, "r") as file:
        lines = [line.strip() for line in file]
        return [line for line in lines if len(line) == 0 or line[0] != "#"]

def load_data():
    global DATA
    DATA = read_file("data/my_data.txt")

Answer 1

是的,这是合乎逻辑的.这些文件是相对于您的工作目录的.您可以通过从其他目录运行脚本来更改它.你可以做的是在运行时获取你正在运行的脚本的目录并从中构建.

import os

def read_file(filename):
    #get the directory of the current running script. "__file__" is its full path
    path, fl = os.path.split(os.path.realpath(__file__))
    #use path to create the fully classified path to your data
    full_path = os.path.join(path, filename)
    with open(full_path, "r") as file:
       #etc