我目前正在使用以下代码将对象编组为xml字符串
JAXBContext context;
try {
context = JAXBContext.newInstance(heartbeat.getClass());
StringWriter writer = new StringWriter();
Marshaller marshaller = context.createMarshaller();
heartbeat.setHeader(header);
heartbeat.setHeartbeatEvent(event);
marshaller.marshal(heartbeat, writer);
String stringXML = writer.toString();
return stringXML;
} catch (JAXBException e) {
throw new RuntimeException("Problems generating XML in specified "
+ "encoding, underlying problem is " + e.getMessage(),
e);
}
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这会产生以下标题
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
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我想要的输出如下
<?xml version=\"1.0\"?>
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通过将此添加到编组器
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, Boolean.FALSE);
marshaller.setProperty("com.sun.xml.bind.xmlHeaders", "<?xml version=\"1.0\"?>");
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我收到
<?xml version="1.0" encoding="UTF-8" standalone="yes"?><?xml version="1.0"?>
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并将JAXB_FRAGMENT属性更改为TRUE将完全删除标头.我一直关注JAXB - 从生成的XML线程中删除'standalone ="yes"'试图解决问题,但到目前为止我没有运气.有人可以给我一些关于如何从JAXB marshaller获取所需标题的见解吗?
bdo*_*han 18
当OutputStream使用以下组合编组到a时会产生预期输出.
marshaller.setProperty("com.sun.xml.bind.xmlHeaders", "<?xml version=\"1.0\"?>");
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
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当您编组到a时,您看到的问题就出现了Writer,这似乎是JAXB参考实现中的错误.您可以通过以下链接提出问题:
你可以随时做:
JAXBContext context;
try {
context = JAXBContext.newInstance(heartbeat.getClass());
StringWriter writer = new StringWriter();
writer.append("<?xml version=\"1.0\"?>");
Marshaller marshaller = context.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FRAGMENT, true);
heartbeat.setHeader(header);
heartbeat.setHeartbeatEvent(event);
marshaller.marshal(heartbeat, writer);
String stringXML = writer.toString();
return stringXML;
} catch (JAXBException e) {
throw new RuntimeException("Problems generating XML in specified "
+ "encoding, underlying problem is " + e.getMessage(),
e);
}
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EclipseLink JAXB(MOXy)也支持它com.sun.xml.bind.xmlHeaders并且在编组时它可以正常工作Writer(我是MOXy主管)
这对我有用
marshaller.setProperty("com.sun.xml.internal.bind.xmlHeaders", "<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
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