use*_*275 1 .net c# visual-studio-2012
我在 VS 2012 中使用 .net c# 并尝试编写一个函数来自动检查已检查父树视图节点的所有子节点。我是 c# 编程新手,所以我发现了以下代码,但它有两个问题:
谢谢你的帮助。
treeView.BeginUpdate();
//Loop through all the nodes of tree
foreach (TreeNode node in treeView.Nodes)
{
//If node has child nodes
if (HasChildNodes(node))
{
if (node.Checked == true)
{
//Check all the child nodes.
foreach (TreeNode childNode in node.Nodes)
{
childNode.Checked = true;
}
}
}
}
treeView.EndUpdate();
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小智 5
以下是树视图示例的工作代码,其中检查和取消检查子节点和父节点(添加树视图并将名称指定为 tvwDynamic)
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
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命名空间 Treeview { 公共部分类 Form1 : Form { 公共 Form1() { InitializeComponent(); } }
private void Form1_Load(object sender, EventArgs e)
{
TreeNode MainNode = new TreeNode("Java");
tvwDynamic.Nodes.Add(MainNode);
MainNode = new TreeNode("PHP");
tvwDynamic.Nodes.Add(MainNode);
TreeNode node2 = new TreeNode("C#");
TreeNode node3 = new TreeNode("VB.NET");
TreeNode[] childNodes = new TreeNode[] {node2,node3};
MainNode = new TreeNode("ASP.NET", childNodes);
tvwDynamic.Nodes.Add(MainNode);
TreeNode node4 = new TreeNode("Winforms");
TreeNode node5 = new TreeNode("Webforms");
TreeNode[] SubchildNodes = new TreeNode[] {node4,node5};
MainNode = new TreeNode("Test",SubchildNodes);
tvwDynamic.Nodes[2].Nodes[1].Nodes.Add(MainNode);
tvwDynamic.CheckBoxes = true;
}
private void tvwDynamic_AfterCheck(object sender, TreeViewEventArgs e)
{
if (e.Action != TreeViewAction.Unknown)
{
if (e.Node.Nodes.Count > 0)
{
/* Calls the CheckAllChildNodes method, passing in the current
Checked value of the TreeNode whose checked state changed. */
this.CheckAllChildNodes(e.Node, e.Node.Checked);
}
}
SelectParents(e.Node, e.Node.Checked);
}
private void CheckAllChildNodes(TreeNode treeNode, bool nodeChecked)
{
foreach (TreeNode node in treeNode.Nodes)
{
node.Checked = nodeChecked;
if (node.Nodes.Count > 0)
{
// If the current node has child nodes, call the CheckAllChildsNodes method recursively.
this.CheckAllChildNodes(node, nodeChecked);
}
}
}
private void SelectParents(TreeNode node, Boolean isChecked)
{
var parent = node.Parent;
if (parent == null)
return;
if (!isChecked && HasCheckedNode(parent))
return;
parent.Checked = isChecked;
SelectParents(parent, isChecked);
}
private bool HasCheckedNode(TreeNode node)
{
return node.Nodes.Cast<TreeNode>().Any(n => n.Checked);
}
} }
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