设置Backbone.View的动态css样式属性

Question

我正在尝试设置<ul>元素的高度,宽度和背景图像.

这是我的Backbone.View所拥有的:

var RackView = Backbone.View.extend({

    tagName: 'ul',

    className: 'rack unselectable',

    template: _.template($('#RackTemplate').html()),

    render: function () {
        this.$el.html(this.template(this.model.toJSON()));
        return this;
    },

    attributes: function () {
        var isFront = this.model.get('isFront');
        var imageUrlIndex = isFront ? 0 : 1;

        return {
            'background-image': 'url(' + this.model.get('imageUrls')[imageUrlIndex] + ')',
            'height': this.model.get('rows') + 'px',
            'width': this.model.get('width') + 'px'
        };
    }
}

这不起作用,因为属性不会写入元素的"样式"属性.相反,它们被视为属性...因为函数名称而有意义,但它让我想知道 - 我如何正确地实现这样的事情？

设置后图像,高度和宽度是不可变的,如果这有助于简化...

我只是以一种风格包裹我的回报吗？这似乎过于复杂......

这是生成的HTML:

<ul background-image="url(data:image/png;base64,...)" height="840px" width="240px" class="rack unselectable">
</ul>

编辑:这有效,但我没有激怒:

attributes: function () {

    var isFront = this.model.get('isFront');
    var imageUrlIndex = isFront ? 0 : 1;

    var backgroundImageStyleProperty = "background-image: url(" + this.model.get('imageUrls')[imageUrlIndex] + ");";
    var heightStyleProperty = "height: " + this.model.get('rows') + 'px;';
    var widthStyleProperty = "width: " + this.model.get('width') + 'px;';

    return {
        'style': backgroundImageStyleProperty + ' ' + heightStyleProperty + ' ' + widthStyleProperty
    };
},

Answer 1

您可以在函数中使用jquery css render函数:

render: function () {
    this.$el.html(this.template(this.model.toJSON()));
    var backgroundImageStyleProperty = "background-image: url(" + this.model.get('imageUrls')[imageUrlIndex] + ");";
    var heightStyleProperty = "height: " + this.model.get('rows') + 'px;';
    var widthStyleProperty = "width: " + this.model.get('width') + 'px;';

    this.$el.css({
     'height'          : heightStyleProperty,
     'width'           : widthStyleProperty,
     'background-image': backgroundImageStyleProperty
    });

    return this;
},