Ham*_*shi 16 mysql database-design foreign-keys relational-database
我试图创建一个varchar列作为外键的表,但MySql在创建表时给出了一个错误.我的查询是这样的:
CREATE TABLE network_classes (
id TINYINT(1) UNSIGNED NOT NULL AUTO_INCREMENT,
category VARCHAR(80) NOT NULL,
PRIMARY KEY(id),
KEY `key_1` (`id`,`category`)
)
ENGINE=InnoDB;
CREATE TABLE networks (
id TINYINT(3) UNSIGNED NOT NULL AUTO_INCREMENT,
name VARCHAR(100) NOT NULL,
category VARCHAR(80) NOT NULL,
director_id TINYINT(3) UNSIGNED NULL,
director_name VARCHAR(100) NULL,
description VARCHAR(1000) NULL,
last_modified TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
user_id SMALLINT UNSIGNED NULL,
PRIMARY KEY(id),
KEY `networks_fk1` (`category`),
CONSTRAINT `networks_fk1` FOREIGN KEY (`category`) REFERENCES `network_classes` (`category`) ON DELETE NO ACTION,
INDEX networks_index2471(name),
INDEX networks_index2472(director_id, director_name)
)
ENGINE=InnoDB;
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我收到此错误:
[Err] 1215 - Cannot add foreign key constraint
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我使用的是MySQL 5.6.12.如何重写我的查询来修复它?
nei*_*ldt 24
您只能使用引用唯一字段的外键.修改您的network_classes表,以便类别字段是唯一的,如下所示
CREATE TABLE network_classes (
id TINYINT(1) UNSIGNED NOT NULL AUTO_INCREMENT,
category VARCHAR(80) NOT NULL,
PRIMARY KEY(id),
UNIQUE KEY `category_UNIQUE` (`category`),
KEY `key_1` (`id`,`category`)
)
ENGINE=InnoDB;
CREATE TABLE networks (
id TINYINT(3) UNSIGNED NOT NULL AUTO_INCREMENT,
name VARCHAR(100) NOT NULL,
category VARCHAR(80) NOT NULL,
director_id TINYINT(3) UNSIGNED NULL,
director_name VARCHAR(100) NULL,
description VARCHAR(1000) NULL,
last_modified TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP,
user_id SMALLINT UNSIGNED NULL,
PRIMARY KEY(id),
KEY `networks_fk1` (`category`),
CONSTRAINT `networks_fk1` FOREIGN KEY (`category`) REFERENCES `network_classes` (`category`) ON DELETE NO ACTION,
INDEX networks_index2471(name),
INDEX networks_index2472(director_id, director_name)
)
ENGINE=InnoDB;
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然后,您应该能够添加所需的外键
表中的列类型和引用的表与约束不匹配
为什么2个相同大小的varchar列在类型上不匹配?当然答案是明显的整理.事实证明,在新表中,列是UTF-8而不是引用表中的ASCII.改为ascii并完成.
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