C#XML文档中存在错误(2,2)

Question

我正在尝试反序列化以下XML:

<?xml version="1.0" encoding="UTF-8"?>
<XGResponse><Failure code="400">
    Message id &apos;1&apos; was already submitted.
</Failure></XGResponse>

通过这个电话:

[...]
    var x = SerializationHelper.Deserialize<XMLGateResponse.XGResponse>(nResp);
[...]        

public static T Deserialize<T>(string xml)
{
    using (var str = new StringReader(xml))
    {
        var xmlSerializer = new XmlSerializer(typeof(T));
        return (T)xmlSerializer.Deserialize(str);
    }
}

获取相应类的实例:

//------------------------------------------------------------------------------
// <auto-generated>
//     This code was generated by a tool.
//     Runtime Version:4.0.30319.18052
//
//     Changes to this file may cause incorrect behavior and will be lost if
//     the code is regenerated.
// </auto-generated>
//------------------------------------------------------------------------------

using System.Xml.Serialization;

// 
// This source code was auto-generated by xsd, Version=4.0.30319.1.
// 

namespace XMLGateResponse
{

    /// <remarks/>
    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/XMLGateResponse")]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "http://tempuri.org/XMLGateResponse", IsNullable = false)]
    public partial class XGResponse
    {

        private object[] itemsField;

        /// <remarks/>
        [System.Xml.Serialization.XmlElementAttribute("Failure", typeof(Failure))]
        [System.Xml.Serialization.XmlElementAttribute("Success", typeof(Success))]
        public object[] Items
        {
            get
            {
                return this.itemsField;
            }
            set
            {
                this.itemsField = value;
            }
        }
    }

    /// <remarks/>
    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/XMLGateResponse")]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "http://tempuri.org/XMLGateResponse", IsNullable = false)]
    public partial class Failure
    {

        private string codeField;

        private string titleField;

        private string valueField;

        /// <remarks/>
        [System.Xml.Serialization.XmlAttributeAttribute(DataType = "NMTOKEN")]
        public string code
        {
            get
            {
                return this.codeField;
            }
            set
            {
                this.codeField = value;
            }
        }

        /// <remarks/>
        [System.Xml.Serialization.XmlAttributeAttribute()]
        public string title
        {
            get
            {
                return this.titleField;
            }
            set
            {
                this.titleField = value;
            }
        }

        /// <remarks/>
        [System.Xml.Serialization.XmlTextAttribute()]
        public string Value
        {
            get
            {
                return this.valueField;
            }
            set
            {
                this.valueField = value;
            }
        }
    }

    /// <remarks/>
    [System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")]
    [System.SerializableAttribute()]
    [System.Diagnostics.DebuggerStepThroughAttribute()]
    [System.ComponentModel.DesignerCategoryAttribute("code")]
    [System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true, Namespace = "http://tempuri.org/XMLGateResponse")]
    [System.Xml.Serialization.XmlRootAttribute(Namespace = "http://tempuri.org/XMLGateResponse", IsNullable = false)]
    public partial class Success
    {

        private string titleField;

        /// <remarks/>
        [System.Xml.Serialization.XmlAttributeAttribute()]
        public string title
        {
            get
            {
                return this.titleField;
            }
            set
            {
                this.titleField = value;
            }
        }
    }
}

但它提出了错误There is an error in XML document (2, 2).
我现在已经找了一个解决方案大约一个小时,但它没有多大帮助.

我甚至尝试了一些不应做的事情:

public static T Deserialize<T>(string xml)
{
    [...]
        var xmlSerializer = new XmlSerializer(typeof(T), new XmlRootAttribute(typeof(T).Name));
    [...]
}

然而,这确实可以防止错误发生.但是因为它只实现了将XMLGateResponse.XGResponse实例完全为空(每个元素/属性都为空),所以它并不是真正的改进.

我知道这个问题There is an error in XML document (2, 2)已经讨论了很多,但我真的找不到适合我的解决方案.

Answer 1

如果您尝试反序列化为错误的类型,您可能会得到相同的错误.
例如,如果你打电话

Deserialize<object>(myXml)

要么

Deserialize<Failure>(myXml)

我知道回答Q是一个不好的做法,1)答案已经提供,2)答案并不是提问者要求的答案; 但我认为这可能会节省一些时间让别人在这里找到他们的方式,问题与提问者完全不同.

Answer 2

XGResponse用一个XmlRootAttribute指定默认的namspace名称,但你的文档没有.

删除此命名空间声明或添加xmlns="http://tempuri.org/XMLGateResponse"到xml的根元素