我有一个简单的JPA映射,但我不断得到一个Could not determine type for例外.设置器和getter被省略.
@Entity
@Inheritance(strategy = InheritanceType.JOINED)
public class SupervisionCommand {
@Id
@GeneratedValue
protected Long id;
}
@Entity
public class MySupervisionCommand extends SupervisionCommand {
}
@Entity
public class Job {
@Id
@GeneratedValue
private Long id;
private SupervisionCommand command;
}
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完整的异常消息: Could not determine type for: com.family.model.SupervisionCommand, at table: job, for columns: [org.hibernate.mapping.Column(command)]
JB *_*zet 10
您需要在命令上使用OneToOne或ManyToOne注释(取决于实际的基数):
@ManyToOne
private SupervisionCommand command;
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字段的默认映射是@Column.并且Hibernate不知道使用哪种类型的列(varchar?number?)来存储SuperVisionCommand实例.如果它实现了Serializable,Hibernate会将它序列化并将其存储在BLOB列中,但这不是你想要的.
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