如何在Android上使用Google URL Shortener API?

Ogr*_*gre 6 android google-url-shortener

在尝试自己导入库之后,我终于设法发现我可以使用Google Plugin for Eclipse这样做.

但是,我似乎无法找到如何在Android上实际使用API​​的任何示例,至少没有可编译的,因为这些示例中所需的类似乎无法由Eclipse解析,所以我只能假设这些Google Plugin for Eclipse为URL Shortener API导入的库中不存在类.我能找到的最接近的例子就是这里,它似乎是针对谷歌应用引擎,而不是Android,并使用我似乎无法访问的类.

所以问题是,如何在Android应用程序中使用此API来获取URL的缩短版本?我希望使用API​​密钥代替OAuth.

Sat*_*eri 7

首先在谷歌控制台上创建一个项目并启用url shortner api并获取api密钥,然后使用以下Asynctask来缩短网址.

 public class newShortAsync extends AsyncTask<Void,Void,String> {

        String longUrl="http://stackoverflow.com/questions/18372672/how-do-i-use-the-google-url-shortener-api-on-android/20406915";
        @Override
        protected void onPreExecute() {
            super.onPreExecute();
            progressBar.setVisibility(View.VISIBLE);
         }

        @Override
        protected void onPostExecute(String s) {
            super.onPostExecute(s);
            progressBar.setVisibility(View.GONE);
            System.out.println("JSON RESP:" + s);
            String response=s;
            try {
                JSONObject jsonObject=new JSONObject(response);
                id=jsonObject.getString("id");
                System.out.println("ID:"+id);
            } catch (JSONException e) {
                e.printStackTrace();
            }
        }

        @Override
        protected String doInBackground(Void... params) {
            BufferedReader reader;
            StringBuffer buffer;
            String res=null;
            String json = "{\"longUrl\": \""+longUrl+"\"}";
            try {
                URL url = new URL("https://www.googleapis.com/urlshortener/v1/url?key=YOUR_API_KEY");
                HttpURLConnection con = (HttpURLConnection) url.openConnection();
                con.setReadTimeout(40000);
                con.setConnectTimeout(40000);
                con.setRequestMethod("POST");
                con.setRequestProperty("Content-Type", "application/json");
                OutputStream os = con.getOutputStream();
                BufferedWriter writer = new BufferedWriter(
                        new OutputStreamWriter(os, "UTF-8"));

                writer.write(json);
                writer.flush();
                writer.close();
                os.close();

                int status=con.getResponseCode();
                InputStream inputStream;
                if(status==HttpURLConnection.HTTP_OK)
                inputStream=con.getInputStream();
                else
                    inputStream = con.getErrorStream();

                reader= new BufferedReader(new InputStreamReader(inputStream));

                buffer= new StringBuffer();

                String line="";
                while((line=reader.readLine())!=null)
                {
                    buffer.append(line);
                }

                res= buffer.toString();

            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (ProtocolException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return res;




        }
    }
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然后只需执行此asynctask,您将获得一个json响应,其中存在id,这只是缩短的Url.


bab*_*bay 4

  1. 添加到节点中的清单application
 <meta-data
         android:name="com.google.android.urlshortener.API_KEY"
         android:value="{YOUR_API_KEY}"/>
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  1. 添加以下库:

google-api-client-1.17.0-rc.jar

google-api-client-android-1.17.0-rc.jar

google-api-services-urlshortener-v1-rev22-1.17.0-rc.jar

谷歌-http-client-1.17.0-rc.jar

谷歌-http-client-android-1.17.0-rc.jar

  1. 方法:

       String shorten(String longUrl){
    
       Urlshortener.Builder builder = new Urlshortener.Builder (AndroidHttp.newCompatibleTransport(), AndroidJsonFactory.getDefaultInstance(), null);
       Urlshortener urlshortener = builder.build();
    
        com.google.api.services.urlshortener.model.Url url = new Url();
        url.setLongUrl(longUrl);
        try {
           url = urlshortener.url().insert(url).execute();
            return url.getId();
        } catch (IOException e) {
            return null;
       }
    }
    
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