Python - Pymongo插入和更新文档

Dus*_*tin 13 python mongodb pymongo

使用PyMongo,我在列表中有一组dict,我想提交给我的MongoDB.列表中的某些项目是新条目,有些是要更新的.

例:

在服务器数据库:

[{"_id" : 1, "foo" : "bar}]
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要发送到数据库:

[{"_id" : 1, "foo" : "HELLO"}, {"_id" : 2, "Blah" : "Bloh"}]
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我目前正在使用以下内容来插入文档,但我将如何执行上述内容?任何帮助表示赞赏!

collection.insert(myDict)
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Rom*_*kar 22

使用upsert选项:

from pymongo import MongoClient
cl = MongoClient()
coll = cl["local"]["test2"]

data = [{"_id" : 1, "foo" : "HELLO"}, {"_id" : 2, "Blah" : "Bloh"}]
for d in data:
    coll.update({'_id':d['_id']}, d, True)
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  • 有没有办法通过单个API调用执行此操作?类似于"批量"更新的东西,以获得更好的性能. (4认同)

lov*_*esh 7

您也可以使用保存

import pymongo
con = pymongo.MongoClient()
coll = con.db_name.collection_name

docs = [{"_id" : 1, "foo" : "HELLO"}, {"_id" : 2, "Blah" : "Bloh"}]

for doc in docs:
    coll.save(doc)
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The*_*eMI 5

对于 pymongo 3.0 及更高版本:

import pymongo
con = pymongo.MongoClient()
collection = con.db_name.collection_name

docs = [{"_id" : 1, "foo" : "HELLO"}, {"_id" : 2, "Blah" : "Bloh"}]
for d in docs:
    collection.update_many({'_id':d['_id']}, d,True)
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参考: http: //api.mongodb.org/python/current/api/pymongo/collection.html


Seb*_*CHA 5

您必须使用upsert来更新(或插入)您的数据

from pymongo import MongoClient
client = MongoClient()
collection = client.my_database.my_collection

objects = [{"_id" : 1, "foo" : "HELLO"}, {"_id" : 2, "Blah" : "Bloh"}]
for obj in objects:
     collection.replace_one({"_id": obj["_id"]}, obj, upsert=True) 

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不推荐使用replace_oneupdate方法:

https://api.mongodb.com/python/current/api/pymongo/collection.html#pymongo.collection.Collection.replace_one

如果要使用批量更新:

from pymongo import ReplaceOne

update_objects = list()
for obj in objects:
    update_objects.append(ReplaceOne( {'_id': obj['_id']},  obj, upsert=True))

collection.bulk_write(update_objects)
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