如何将目录中最旧的10个文件移动到另一个目录

Question

我有一个C#脚本,目前正在两个目录之间移动文件.它一次移动10个文件.问题是它是按文件名抓取10个文件.我希望它每次运行时都能获取最早的10个文件.我怎样才能做到这一点？

目前,我的脚本如下所示:

string[] dirsSourceDirectory = System.IO.Directory.GetDirectories(sourceDirectory);
string[] filesSourceDirectory = System.IO.Directory.GetFiles(sourceDirectory);
string[] dirsDestinationDirectory = System.IO.Directory.GetDirectories(destinationDirectory);
string[] filesDestinationDirectory = System.IO.Directory.GetFiles(destinationDirectory);
int filecount = Directory.GetFiles(destinationDirectory, "*.TRN", SearchOption.TopDirectoryOnly).Length;

for (int i = 1; i <= 10; i++)
    {
       FileInfo[] rgfiles = di.GetFiles();
       rgfiles[0].MoveTo(System.IO.Path.Combine(destinationDirectory, rgfiles[0].Name));
    }

谢谢!

Answer 1

var filesToMove = di
  .GetFiles()
  .OrderBy(f => f.CreationTime)
  .Take(10)
  .ToArray();

foreach (var rgFile in filesToMove)
{
   rgfile.MoveTo(System.IO.Path.Combine(destinationDirectory, rgfile.Name));
}