Perl中的CPU /内核数量

use*_*024 14 perl

如何获取Perl中的CPU或内核数量.我想要这个,决定动态创建线程数.下面我创建了3个主题.但我想根据该机器中的核心数创建线程.

#!/usr/bin/perl -w
use threads;
use Thread::Semaphore;

my $semaphore = Thread::Semaphore->new();`enter code here`
my $cur_dir   = "D:\\qout";
opendir( CURDIR, "$cur_dir" );
my @file_list : shared = readdir(CURDIR);
closedir(CURDIR);


$thr1 = threads->create( \&changemode, \@file_list, "th1" );
$thr2 = threads->create( \&changemode, \@file_list, "th2" );
$thr3 = threads->create( \&changemode, \@file_list, "th3" );

sub &changemode {

    my ($file_list) = shift;
    my ($message)   = shift;
    my ($i)         = shift;
    while (@{$file_list}) {
        my $fname;
        $semaphore->down();
        if (@{$file_list}) {
            $fname = shift(@{$file_list});
        }
        $semaphore->up();
        print("$message got access of $fname\n");
        system ("csh -fc \"chmod +w $fname\"");
        #sleep (2);
    }
}


$thr1->join();

$thr2->join();

$thr3->join();
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Bri*_*new 14

查看CPAN模块,例如Sys :: Info :: Device :: CPU

   use Sys::Info;
   use Sys::Info::Constants qw( :device_cpu );
   my $info = Sys::Info->new;
   my $cpu  = $info->device( CPU => %options );

   printf "CPU: %s\n", scalar($cpu->identify)  || 'N/A';
   printf "CPU speed is %s MHz\n", $cpu->speed || 'N/A';
   printf "There are %d CPUs\n"  , $cpu->count || 1;
   printf "CPU load: %s\n"       , $cpu->load  || 0;
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oᴉɹ*_*ǝɥɔ 7

老问题,但这里是我如何告诉我的Linux服务器上的CPU数量:

#!/usr/bin/perl
chomp(my $cpu_count = `grep -c -P '^processor\\s+:' /proc/cpuinfo`);
print("CPUs: $cpu_count\n");
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这仅适用于linux/cygwin.从好的方面来说,这个解决方案不需要安装任何额外的perl模块.

编辑:
Barak Dagan建议使用"perl only"解决方案(我还没有测试过):

open my $handle, "/proc/cpuinfo" or die "Can't open cpuinfo: $!\n";
printf "CPUs: %d\n", scalar (map /^processor/, <$handle>) ; 
close $handle;
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