如何获取Perl中的CPU或内核数量.我想要这个,决定动态创建线程数.下面我创建了3个主题.但我想根据该机器中的核心数创建线程.
#!/usr/bin/perl -w
use threads;
use Thread::Semaphore;
my $semaphore = Thread::Semaphore->new();`enter code here`
my $cur_dir = "D:\\qout";
opendir( CURDIR, "$cur_dir" );
my @file_list : shared = readdir(CURDIR);
closedir(CURDIR);
$thr1 = threads->create( \&changemode, \@file_list, "th1" );
$thr2 = threads->create( \&changemode, \@file_list, "th2" );
$thr3 = threads->create( \&changemode, \@file_list, "th3" );
sub &changemode {
my ($file_list) = shift;
my ($message) = shift;
my ($i) = shift;
while (@{$file_list}) {
my $fname;
$semaphore->down();
if (@{$file_list}) {
$fname = shift(@{$file_list});
}
$semaphore->up();
print("$message got access of $fname\n");
system ("csh -fc \"chmod +w $fname\"");
#sleep (2);
}
}
$thr1->join();
$thr2->join();
$thr3->join();
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Bri*_*new 14
查看CPAN模块,例如Sys :: Info :: Device :: CPU
use Sys::Info;
use Sys::Info::Constants qw( :device_cpu );
my $info = Sys::Info->new;
my $cpu = $info->device( CPU => %options );
printf "CPU: %s\n", scalar($cpu->identify) || 'N/A';
printf "CPU speed is %s MHz\n", $cpu->speed || 'N/A';
printf "There are %d CPUs\n" , $cpu->count || 1;
printf "CPU load: %s\n" , $cpu->load || 0;
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老问题,但这里是我如何告诉我的Linux服务器上的CPU数量:
#!/usr/bin/perl
chomp(my $cpu_count = `grep -c -P '^processor\\s+:' /proc/cpuinfo`);
print("CPUs: $cpu_count\n");
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这仅适用于linux/cygwin.从好的方面来说,这个解决方案不需要安装任何额外的perl模块.
编辑:
Barak Dagan建议使用"perl only"解决方案(我还没有测试过):
open my $handle, "/proc/cpuinfo" or die "Can't open cpuinfo: $!\n";
printf "CPUs: %d\n", scalar (map /^processor/, <$handle>) ;
close $handle;
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