如果未在select2插件中定义initSelection()错误,则无法调用val()

Question

我正在使用select2插件来加载远程数据.我正在使用一个返回JSON数据的aspx页面,并将其分配给select2插件.用户从select2文本框中选择一些值后,我强制页面回发.回发后我使用以下代码重新加载以在select2文本框中设置文本.

var data = { "PatientID": "XYX", "Email": "testing@gmail.com" };

            $('#e6').select2('val', '123');

但系统抛出以下错误: cannot call val() if initSelection() is not defined

即使我定义了init,我也无法设置值.我正在使用以下代码.请帮我在回发后设置select2文本框上的值.

$(document).ready(function () {
        $("#e6").select2({
            placeholder: "Search for a movie",
            minimumInputLength: 1,
            ajax: { // instead of writing the function to execute the request we use Select2's convenient helper
                url: "data.aspx", 
                dataType: 'json',
                quietMillis: 1000,
                data: function (term, page) {
                    return {
                        name: term
                    };
                },
                initSelection: function (element, callback) {
                    var data = { "PatientID": "XYX", "Email": "testing@gmail.com" };
                    callback(data);
                },

                results: function (data) {
                    var results = [];
                    $.each(data, function (index, item) {
                        results.push({
                            id: item['Email'],
                            text: item['PatientID']
                        });
                    });
                    return {
                        results: results
                    };
                },
            },
        });

    });

    window.onload = function () {
        var data = { "PatientID": "XYX", "Email": "testing@gmail.com" };
        //When this is called system is throwing error
        //This code is required to show the value in select2 textbox after the post back
        $('#e6').select2('val', data);
    }

    $(document).ready(function () {
        $("#e6").on("select2-selecting", function (e) {
            //alert("selecting val=" + e.val + " choice=" + JSON.stringify(e.choice));
            var id = document.getElementById('<%= savebtn.ClientID %>');
            document.getElementById('<%= hdnFld.ClientID %>').value = e.val;
            id.value = e.val;
            //causes post back
            id.click();

        });
    });

Answer 1

你犯了错误!我遇到了这个问题而且我看到了你的问题.然后我读了Select2的API文档和fount,我错了.Pleas把initSelection和ajax.like放在一起:

$("#e6").select2({
        placeholder: "Search for a movie",
        minimumInputLength: 1,
        initSelection: function (element, callback) {
                var data = { "PatientID": "XYX", "Email": "testing@gmail.com" };
                callback(data);
            },
        ajax: { // instead of writing the function to execute the request we use Select2's convenient helper
            url: "data.aspx", 
            dataType: 'json',
            quietMillis: 1000,
            data: function (term, page) {
                return {
                    name: term
                };
            },


            results: function (data) {
                var results = [];
                $.each(data, function (index, item) {
                    results.push({
                        id: item['Email'],
                        text: item['PatientID']
                    });
                });
                return {
                    results: results
                };
            },
        },
    });