将json twitter字符串反序列化为对象

Question

使用下面的URL我试图拉动一个特定的屏幕名称有效的追随者.当我尝试将代码反序列化为一个ojbect时,我会在下面找到任何想法的错误消息.我也把代码用于Json类型..我想获得位置归档.我已经发布用户本身就是一个对象.所以我可以得到一个例子,它将让我对初始对象进行脱盐,然后将对象放入其中.

URL = "https://api.twitter.com/1.1/followers/list.json?&screen_name="will insert here "

反序列化为objec代码

var result = JsonConvert.DeserializeObject<List>(FollowerData)

Json类型代码

public class Follower
{

[JsonProperty("created_at")]
public string CreatedAt { get; set; }

[JsonProperty("id")]
public string Id { get; set; }

[JsonProperty("id_str")]
public string IdStr { get; set; }

[JsonProperty("name")]
public string Name { get; set; }

[JsonProperty("screen_name")]
public string ScreenName { get; set; }

[JsonProperty("location")]
public bool Location { get; set; }

[JsonProperty("description")]
public string Description { get; set; }

}

错误信息

{"不能反序列化当前JSON对象(例如{\"名称\":\"值\"})成型'System.Collections.Generic.List`1 [OAuthTwitterWrapper.JsonTypes.FollowerUsers]’,因为类型要求JSON数组(例如[1,2,3])以正确反序列化.\ r \n要修复此错误要么将JSON更改为JSON数组(例如[1,2,3]),要么更改反序列化类型以使其成为正常.NET类型(例如不是原始类型像整数,而不是集合类型等的阵列或列表),其可以从一个JSON对象反序列化.JsonObjectAttribute也可以添加到该类型迫使它从JSON对象反序列化.\r \n路径'用户',第1行,第9位."}

Json String Examplt

{
    "users": [
        {
            "id": 219566993,
            "id_str": "219566993",
            "name": "belenastorgano",
            "screen_name": "anna_belenn_",
            "location": "CapitalFederal, Argentina",
            "description": "Mesientonomade, todav\\u00edanotengounlugarfijodondevivir.-",
            "url": null,
            "entities": {
                "description": {
                    "urls": []
                }
            },
            "protected": true,
            "followers_count": 44,
            "friends_count": 64,
            "listed_count": 0,
            "created_at": "ThuNov2506: 28: 12+00002010",
            "favourites_count": 1,
            "utc_offset": -10800,
            "time_zone": "BuenosAires",
            "geo_enabled": true,
            "verified": false,
            "statuses_count": 207,
            "lang": "es",
            "contributors_enabled": false,
            "is_translator": false,
            "profile_background_color": "599E92",
            "profile_background_image_url": "http: \\/\\/a0.twimg.com\\/images\\/themes\\/theme18\\/bg.gif",
            "profile_background_image_url_https": "https: \\/\\/si0.twimg.com\\/images\\/themes\\/theme18\\/bg.gif",
            "profile_background_tile": false,
            "profile_image_url": "http: \\/\\/a0.twimg.com\\/profile_images\\/378800000326157070\\/e91b8fd8e12eda0a7fa350dcd286c56a_normal.jpeg",
            "profile_image_url_https": "https: \\/\\/si0.twimg.com\\/profile_images\\/378800000326157070\\/e91b8fd8e12eda0a7fa350dcd286c56a_normal.jpeg",
            "profile_link_color": "E05365",
            "profile_sidebar_border_color": "EEEEEE",
            "profile_sidebar_fill_color": "F6F6F6",
            "profile_text_color": "333333",
            "profile_use_background_image": true,
            "default_profile": false,
            "default_profile_image": false,
            "following": null,
            "follow_request_sent": null,
            "notifications": null
        }
    ],
    "next_cursor": 1443863551966642400,
    "next_cursor_str": "1443863551966642309",
    "previous_cursor": 0,
    "previous_cursor_str": "0"
}

Answer 1

我需要的唯一字段是用户表中的位置

你不需要任何类来从你的json中获取一些字段.只是利用dynamic

dynamic dynObj = JsonConvert.DeserializeObject(json); 
Console.WriteLine(dynObj.users[0].location);